Polynomials : Polynomials Created by:-
IX-A Introduction : Introduction An algebraic expression in which variables involved have only non-negative integral powers is called a polynomial.
E.g.- (a) 2x3–4x2+6x–3 is a polynomial in one variable x.
(b) 8p7+4p2+11p3-9p is a polynomial in one variable p.
(c) 4+7x4/5+9x5 is an expression but not a polynomial
since it contains a term x4/5, where 4/5 is not
a non-negative integer. Degree of a Polynomial in one variable. : Degree of a Polynomial in one variable. What is degree of the following binomial? The answer is 2. 5x2 + 3 is a polynomial in x of degree 2. In case of a polynomial in one variable, the highest power of the variable is called the degree of polynomial. Degree of a Polynomial in two variables. : Degree of a Polynomial in two variables. What is degree of the following polynomial? In case of polynomials on more than one variable, the sum of powers of the variables in each term is taken up and the highest sum so obtained is called the degree of polynomial. The answer is five because if we add 2 and 3 , the answer is five which is the highest power in the whole polynomial. E.g.- is a polynomial in x
and y of degree 7. Polynomials in one variable : Polynomials in one variable A polynomial is a monomial or a sum of monomials.
Each monomial in a polynomial is a term of the polynomial.
The number factor of a term is called the coefficient.
The coefficient of the first term in a polynomial is the lead coefficient.
A polynomial with two terms is called a binomial.
A polynomial with three term is called a trinomial. Polynomials in one variable : Polynomials in one variable The degree of a polynomial in one variable is the largest exponent of that variable. A constant has no variable. It is a 0 degree polynomial. This is a 1st degree polynomial. 1st degree polynomials are linear. This is a 2nd degree polynomial. 2nd degree polynomials are quadratic. This is a 3rd degree polynomial. 3rd degree polynomials are cubic. Examples : Examples Text Text Txt Text Text Standard Form : Standard Form Phase 1 Phase 2 To rewrite a polynomial in standard form, rearrange the terms of the polynomial starting with the largest degree term and ending with the lowest degree term. The leading coefficient, the coefficient of the first term in a polynomial written in standard form, should be positive. How to convert a polynomial into standard form? Remainder Theorem : Remainder Theorem TEXT TEXT TEXT TEXT Let f(x) be a polynomial of degree n > 1 and let a be any real number.
When f(x) is divided by (x-a) , then the remainder is f(a). PROOF Suppose when f(x) is divided by (x-a), the quotient is g(x) and the remainder
Then, degree r(x) < degree (x-a)
degree r(x) < 1 [ therefore, degree (x-a)=1]
degree r(x) = 0
r(x) is constant, equal to r (say)
Thus, when f(x) is divided by (x-a), then the quotient is g9x) and the remainder is r.
Therefore, f(x) = (x-a)*g(x) + r (i)
Putting x=a in (i), we get r = f(a)
Thus, when f(x) is divided by (x-a), then the remainder is f(a). Questions on Remainder Theorem : Questions on Remainder Theorem Q.) Find the remainder when the polynomial
f(x) = x4 + 2x3 – 3x2 + x – 1 is divided by (x-2). A.) x-2 = 0 x=2
By remainder theorem, we know that when f(x) is divided by (x-2), the remainder is x(2).
Now, f(2) = (24 + 2*23 – 3*22 + 2-1)
= (16 + 16 – 12 + 2 – 1) = 21.
Hence, the required remainder is 21. Factor Theorem : Factor Theorem Let f(x) be a polynomial of degree n > 1 and let a be
any real number.
If f(a) = 0 then (x-a) is a factor of f(x).
PROOF let f(a) = 0
On dividing f(x) by 9x-a), let g(x) be the quotient. Also, by remainder theorem, when f(x) is divided by (x-a), then the remainder is f(a).
therefore f(x) = (x-a)*g(x) + f(a)
f(x) = (x-a)*g(x) [therefore f(a)=0(given]
(x-a) is a factor of f(x). Algebraic Identities : Algebraic Identities Some common identities used to factorize polynomials (x+a)(x+b)=x2+(a+b)x+ab (a+b)2=a2+b2+2ab (a-b)2=a2+b2-2ab a2-b2=(a+b)(a-b) Algebraic Identities : Algebraic Identities Advanced identities used to factorize polynomials (x+y+z)2=x2+y2+z2+2xy+2yz+2zx (x-y)3=x3-y3-3xy(x-y) (x+y)3=x3+y3+3xy(x+y) x3+y3=(x+y) * (x2+y2-xy) x3-y3=(x+y) * (x2+y2+xy) Q/A on Polynomials : Q/A on Polynomials Q.1) Show that (x-3) is a factor of polynomial
A.1) By factor theorem, (x-3) will be a factor of f(x) if f(3)=0.
(x-3) is a factor of f(x).
Hence, (x-3) is a factor of the given polynomial f(x). Q/A on Polynomials : Q/A on Polynomials Q.1) Factorize:
(i) 9x2 – 16y2 (ii)x3-x
A.1)(i) (9x2 – 16y2) = (3x)2 – (4y)2
= (3x + 4y)(3x – 4y)
therefore, (9x2-16y2) = (3x + 4y)(3x – 4y)
(ii) (x3-x) = x(x2-1)
therefore, (x3-x) = x(x + 1)(x-1) Points to Remember : Points to Remember A real number ‘a’ is a zero of a polynomial p(x) if p(a)=0. In this case, a is also called a root of the equation p(x)=0.
Every linear polynomial in one variable has a unique zero, a non-zero constant polynomial has no zero, and every real number is a zero of the zero polynomial. THANK YOU : THANK YOU