# Some Applications on Trignometry

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Category: Education

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### PowerPoint Presentation:

Some Applications on Trignometry

### What is Trignometry?:

What is Trignometry ? T rigonometry is a branch of mathematics that studies triangles and the relationships between their sides and the angles between these sides.

### PowerPoint Presentation:

In this topic we shall make use of Trignometric Ratios to find the height of a tree,a tower,a water tank,width of a river,distance of ship from lighthouse etc.

### Line of Sight:

Line of Sight We observe generally that children usually look up to see an aeroplane when it passes overhead.This line joining their eye to the plane,while looking up is called Line of sight

### PowerPoint Presentation:

Line of Sight Line of Sight Horizontal

### Angle of Elevation :

Angle of Elevation The angle which the line of sight makes with a horizontal line drawn away from their eyes is called the angle of Elevation of aeroplane from them.

### PowerPoint Presentation:

Line of Sight Horizontal Angel of Elevation Angel of Elevation

### Angel of Depression:

Angel of Depression If the pilot of the aeroplane looks downwards at any object on the ground then the Angle between his line of sight and horizontal line drawn away from his eyes is called Angel of Depression

### PowerPoint Presentation:

Angle of Depression Line of Sight Horizontal Angel of Depression

### Trignometric Ratios :

Trignometric Ratios

### PowerPoint Presentation:

Now let us Solve some problem related to Height and Distance

### The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30°. Find the height of the tower. :

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30°. Find the height of the tower. Let AB be the tower and the angle of elevation from point C (on ground) is 30°. In ΔABC, . Therefore, the height of the tower is

### A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30 °.:

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 30 °. Sol:- It can be observed from the figure that AB is the pole. In ΔABC, Therefore, the height of the pole is 10 m.

### A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string. :

A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string. Let K be the kite and the string is tied to point P on the ground. In ΔKLP, . Hence, the length of the string is

### PowerPoint Presentation:

A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30 ° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree. Let AC was the original tree. Due to storm, it was broken into two parts. The broken part In , is making 30° with the ground.

### PowerPoint Presentation:

Height of tree = . + BC Hence, the height of the tree is

### The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m. from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m. :

The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m. from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m. Let AQ be the tower and R, S are the points 4m, 9m away from the base of the tower respectively. The angles are complementary. Therefore, if one angle is θ, the other will be 90 − θ. In ΔAQR,

### PowerPoint Presentation:

In ΔAQS, On multiplying equations ( i ) and ( ii ), we obtain However, height cannot be negative. Therefore, the height of the tower is 6 m.