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LINEAR PROGRAMMING – DUAL :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 1 www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS LINEAR PROGRAMMING – DUAL AFTERSCHO? OL
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LINEAR PROGRAMMING – DUAL :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 2 www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS LINEAR PROGRAMMING – DUAL Dr. T.K. Jain.
AFTERSCHO?OL
Centre for social entrepreneurship
Bikaner M: 9414430763
tkjainbkn@yahoo.co.in
www.afterschool.tk, www.afterschoool.tk
STEPS… :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 3 STEPS… Put the primal in such a way that all requirements are put as constraints.
If it is maximising problem, then convert it into less than or equal to type of inequality
If it is a minimising problem, then convert it into a greater than or equal to (>=) inequality.
If there is any wrong sign, convert it by multiplying it to (-1)
If there is some equation, then convert it into 2 inequalities – one of less than type and one of greater than type.
Some fundamental rules… :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 4 Some fundamental rules… If primal is a minimisation problem, its dual will be a maximisation problem
The number of variables in dual will be equal to number of constraints in the primal
We convert the constraints into the coeffient of the dual objective and vice versa.
If primal is a maximisation problem, with less than or equal to constraints, the dual will be a minimisation problem with greater than or equal to constraints (and vice versa also holds good).
Example… :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 5 Example… Minimise : Z = X1+X2+X3
Constraings :
2X1 – 2X2 = 5
X1 – 3X2 +4X3 = 5
X1>=0, X2>=0, X3 is unrestricted.
New problem (dual). … :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 6 New problem (dual). … Represent the constraints properly.
Minimise : Z = X1+X2+X3
Constraings :
2X1 – 2X2 = 5
X1 – 3X2 +4X3 = 5 (convert it into two equations of inequality)
New solution… :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 7 New solution… Minimise : Z = X1+X2+X3
Constraings :
-2X1 + 2X2 >= - 3 (multiply it by (-1) to make it greater than)
2X2 – X3 >= 5
X1 – 3X2 +4X3 = 5
…. :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 8 …. Minimise : Z = X1+X2+X3
Constraings :
-2X1 + 2X2 >= - 3
2X2 – X3 >= 5
-X1 + 3X2 -4X3 >= - 5
X1 – 3X2 +4X3 >= 5
As X3 is unrestricted, we represent it as X4-X5 :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 9 As X3 is unrestricted, we represent it as X4-X5 Minimise : Z = X1+X2+X4-X5
Constraings :
-2X1 + 2X2 >= - 3
2X2 – X4-X5 >= 5
-X1 + 3X2 -4X4 +4X5 >= - 5
X1 – 3X2 +4X3-4X5 >= 5
Matrix of Primal … :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 10 Matrix of Primal …
Now let us prepare dual :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 11 Now let us prepare dual Maximise : Z= - 3W1 +5W2-5W3+5W4
-2W1+0w2-1w3+1w4 <=1
2w1+2w2+3w3-3w4<=1
0w1 –w2 -4w3 +4w4 <= 1
0w1 +1w2 +4w3-4w4<=1
Now solve it as a normal problem. :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 12 Now solve it as a normal problem.
About AFTERSCHO?OL :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 13 About AFTERSCHO?OL PGPSE - World’s most comprehensive programme on social entrepreneurship – after class 12th
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Branches of AFTERSCHO?OL :www.afterschoool.tk AFTERSCHO?OL's MATERIAL FOR PGPSE PARTICIPANTS 14 Branches of AFTERSCHO?OL PGPSE programme is open all over the world as free online programme.
Those who complete PSPSE have the freedom to start branches of AFTERSCHO?OL
A few branches have already started - one such branch is at KOTA (Rajasthan).
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