Intelligent System Unit III Planning

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Planning The Planning Problem, Planning with State-Space Search, Partial-Order Planning, Planning Graphs, Planning with Prepositional Logic, Analysis of Planning Approaches.

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Intelligent System: Unit III Planning :

Intelligent System: Unit III Planning Reference: Stuart Russell and Peter Norvig

Planning Agent:

Planning Agent environment agent ? sensors actuators A1 A2 A3

Outline:

Outline The Planning problem Planning with State-space search Partial-order planning Planning graphs Planning with propositional logic Analysis of planning approaches

Planning problem:

Planning problem Classical planning environment: fully observable, deterministic, finite, static and discrete. Find a sequence of actions that achieves a given goal when executed from a given initial world state . That is, given a set of action descriptions (defining the possible primitive actions by the agent), an initial state description, and a goal state description or predicate, compute a plan, which is a sequence of action instances, such that executing them in the initial state will change the world to a state satisfying the goal-state description. Goals are usually specified as a conjunction of subgoals to be achieved

Goal of Planning:

Choose actions to achieve a certain goal But isn’t it exactly the same goal as for problem solving? Some difficulties with problem solving: The successor function is a black box : it must be “applied” to a state to know which actions are possible in that state and what are the effects of each one Goal of Planning Otherwise, in the real world an agent would be overwhelmed by irrelevant actions Suppose that the goal is HAVE(MILK). From some initial state where HAVE(MILK) is not satisfied, the successor function must be repeatedly applied to eventually generate a state where HAVE(MILK) is satisfied. An explicit representation of the possible actions and their effects would help the problem solver select the relevant actions

Goal of Planning:

Goal of Planning Choose actions to achieve a certain goal But isn’t it exactly the same goal as for problem solving? Some difficulties with problem solving: The goal test is another black-box function, states are domain-specific data structures, and heuristics must be supplied for each new problem Suppose that the goal is HAVE(MILK)  HAVE(BOOK) Without an explicit representation of the goal, the problem solver cannot know that a state where HAVE(MILK) is already achieved is more promising than a state where neither HAVE(MILK) nor HAVE(BOOK) is achieved

Goal of Planning:

Goal of Planning Choose actions to achieve a certain goal But isn’t it exactly the same goal as for problem solving? Some difficulties with problem solving: The goal may consist of several nearly independent subgoals , but there is no way for the problem solver to know it HAVE(MILK) and HAVE(BOOK) may be achieved by two nearly independent sequences of actions

Representations in Planning:

Representations in Planning Planning opens up the black-boxes by using logic to represent: Actions States Goals Problem solving Logic representation Planning

Major approaches:

Major approaches Situation calculus State space planning Partial order planning Planning graphs Planning with Propositional Logic Hierarchical decomposition (HTN planning) Reactive planning

Situation Calculus Planning:

Situation Calculus Planning Formulate planning problem in FOL Use theorem prover to find proof (aka plan)

Representing change:

Representing change Representing change in the world in logic can be tricky. One way is just to change the KB Add and delete sentences from the KB to reflect changes How do we remember the past, or reason about changes? Situation calculus is another way A situation is a snapshot of the world at some instant in time When the agent performs an action A in situation S1, the result is a new situation S2.

Situations:

Situations

Situation calculus:

Situation calculus A situation is a snapshot of the world at an interval of time during which nothing changes Every true or false statement is made with respect to a particular situation. Add situation variables to every predicate. at(hunter,1,1) becomes at(hunter,1,1,s0): at(hunter,1,1) is true in situation (i.e., state) s0. Add a new function, result(a,s), that maps a situation s into a new situation as a result of performing action a. For example, result(forward, s) is a function that returns the successor state (situation) to s Example: The action agent-walks-to-location-y could be represented by (  x)(  y)(  s) (at(Agent,x,s) ^ ~onbox(s)) -> at(Agent,y,result(walk(y),s))

Situation calculus planning:

Situation calculus planning Initial state : a logical sentence about (situation) S 0 At(Home, S 0 ) ^ ~Have(Milk, S 0 ) ^ ~ Have(Bananas, S 0 ) ^ ~Have(Drill, S 0 ) Goal state : (  s) At(Home,s) ^ Have(Milk,s) ^ Have(Bananas,s) ^ Have(Drill,s) Operators are descriptions of actions:  (a,s) Have(Milk,Result(a,s)) <=> ((a=Buy(Milk) ^ At(Grocery,s))  (Have(Milk, s) ^ a~=Drop(Milk))) Result(a,s) names the situation resulting from executing action a in situation s. Action sequences are also useful: Result'(l,s) is the result of executing the list of actions (l) starting in s: (  s) Result'([],s) = s (  a,p,s) Result'([a|p]s) = Result'(p,Result(a,s))

Situation calculus planning II:

Situation calculus planning II A solution is thus a plan that when applied to the initial state yields a situation satisfying the goal query: At(Home,Result'(p,S 0 )) ^ Have(Milk,Result'(p,S 0 )) ^ Have(Bananas,Result'(p,S 0 )) ^ Have(Drill,Result'(p,S 0 )) Thus we would expect a plan (i.e., variable assignment through unification) such as: p = [Go(Grocery), Buy(Milk), Buy(Bananas), Go(HardwareStore), Buy(Drill), Go(Home)]

SC planning: analysis:

SC planning: analysis This is fine in theory, but remember that problem solving (search) is exponential in the worst case Also, resolution theorem proving only finds a proof (plan), not necessarily a good plan Another important issue: the Frame Problem

The Frame Problem:

The Frame Problem In SC, need not only axioms to describe what changes in each situation, but also need axioms to describe what stays the same (can do this using successor-state axioms) Qualification problem: difficulty in specifying all the conditions that must hold in order for an action to work Ramification problem: difficulty in specifying all of the effects that will hold after an action is taken

So…:

So… we restrict the language and use a special-purpose algorithm (a planner) rather than general theorem prover

Planning language:

Planning language What is a good language? Expressive enough to describe a wide variety of problems. Restrictive enough to allow efficient algorithms to operate on it. Planning algorithm should be able to take advantage of the logical structure of the problem. STRIPS and ADL

General language features:

General language features Representation of states Decompose the world in logical conditions and represent a state as a conjunction of positive literals. Propositional literals: Poor  Unknown FO-literals (grounded and function-free): At(Plane1, Melbourne)  At(Plane2, Sydney) Closed world assumption Representation of goals Partially specified state and represented as a conjunction of positive ground literals A goal is satisfied if the state contains all literals in goal.

General language features:

General language features Representations of actions Action = PRECOND + EFFECT Action(Fly(p,from, to), PRECOND: At(p,from)  Plane(p)  Airport(from)  Airport(to) EFFECT: ¬AT(p,from)  At(p,to)) = action schema (p, from, to need to be instantiated) Action name and parameter list Precondition (conj. of function-free literals) Effect (conj of function-free literals and P is True and not P is false) Add-list vs delete-list in Effect

Language semantics?:

Language semantics? How do actions affect states? An action is applicable in any state that satisfies the precondition. For FO action schema applicability involves a substitution  for the variables in the PRECOND . At(P1,JFK)  At(P2,SFO)  Plane(P1)  Plane(P2)  Airport(JFK)  Airport(SFO) Satisfies : At(p,from)  Plane(p)  Airport(from)  Airport(to) With  = { p/P1,from/JFK,to/SFO } Thus the action is applicable.

Language semantics?:

Language semantics? The result of executing action a in state s is the state s’ s’ is same as s except Any positive literal P in the effect of a is added to s’ Any negative literal ¬P is removed from s’ EFFECT: ¬AT(p,from)  At(p,to): At(P1,SFO)  At(P2,SFO)  Plane(P1)  Plane(P2)  Airport(JFK)  Airport(SFO) STRIPS assumption: (avoids representational frame problem) every literal NOT in the effect remains unchanged

Expressiveness and extensions:

Expressiveness and extensions STRIPS is simplified Important limit: function-free literals Recent extension:Action Description language (ADL) Action(Fly(p:Plane, from: Airport, to: Airport), PRECOND: At(p,from)  (from  to) EFFECT: ¬At(p,from)  At(p,to)) Standardization : Planning domain definition language (PDDL)

Blocks world:

Blocks world The blocks world is a micro-world that consists of a table, a set of blocks and a robot hand. Some domain constraints: Only one block can be on another block Any number of blocks can be on the table The hand can only hold one block Typical representation: ontable(a) ontable(c) on(b,a) handempty clear(b) clear(c) A B C TABLE

State Representation:

State Representation Conjunction of propositions: BLOCK(A), BLOCK(B), BLOCK(C), ON(A,TABLE), ON(B,TABLE), ON(C,A), CLEAR(B), CLEAR(C), HANDEMPTY A B C TABLE

Goal Representation:

Goal Representation A B C Conjunction of propositions: ON(A,TABLE), ON(B,A), ON(C,B) The goal G is achieved in a state S if all the propositions in G are also in S

Action Representation:

Action Representation Unstack(x,y) P = HANDEMPTY, BLOCK(x), BLOCK(y), CLEAR(x), ON(x,y) E =  HANDEMPTY,  CLEAR(x), HOLDING(x),  ON(x,y), CLEAR(y) Precondition: conjunction of propositions Effect: list of literals Means: Remove HANDEMPTY from state Means: Add HOLDING(x) to state

Example:

Example A B C Unstack (C,A) P = HANDEMPTY, BLOCK(C), BLOCK(A), CLEAR(C), ON(C,A) E =  HANDEMPTY,  CLEAR(C), HOLDING(C),  ON(C,A), CLEAR(A) BLOCK(A), BLOCK(B), BLOCK(C) , ON(A,TABLE), ON(B,TABLE), ON(C,A) , CLEAR(B), CLEAR(C) , HANDEMPTY

Example:

Example A B C BLOCK(A), BLOCK(B), BLOCK(C), ON(A,TABLE), ON(B,TABLE), ON(C,A), CLEAR(B), CLEAR(C), HANDEMPTY, HOLDING(C), CLEAR(A) Unstack(C,A) P = HANDEMPTY, BLOCK(C), BLOCK(A), CLEAR(C), ON(C,A) E =  HANDEMPTY,  CLEAR(C), HOLDING(C),  ON(C,A), CLEAR(A)

Action Representation:

Action Representation Action(Unstack(x,y) P: HANDEMPTY, BLOCK(x), BLOCK(y), CLEAR(x), ON(x,y) E:  HANDEMPTY,  CLEAR(x), HOLDING(x),  ON(x,y), CLEAR(y) Action(Stack(x,y) P: HOLDING(x), BLOCK(x), BLOCK(y), CLEAR(y) E: ON(x,y),  CLEAR(y),  HOLDING(x), CLEAR(x), HANDEMPTY Action(PutDown(x) P: HOLDING(x) E: ON(x,TABLE),  HOLDING(x), CLEAR(x), HANDEMPTY Action(Pickup(x) P: HANDEMPTY, BLOCK(x), CLEAR(x), ON(x,TABLE) E:  HANDEMPTY,  CLEAR(x), HOLDING(x),  ON(x,TABLE)

Example: Blocks world (R&N version):

Example: Blocks world (R&N version) Init(On(A, Table)  On(B,Table)  On(C,Table)  Block(A)  Block(B)  Block(C)  Clear(A)  Clear(B)  Clear(C)) Goal(On(A,B)  On(B,C)) Action(Move(b,x,y) PRECOND: On(b,x)  Clear(b)  Clear(y)  Block(b)  (b x)  (b y)  (x y) EFFECT: On(b,y)  Clear(x)  ¬ On(b,x)  ¬ Clear(y)) Action(MoveToTable(b,x) PRECOND: On(b,x)  Clear(b)  Block(b)  (b x) EFFECT: On (b,Table)  Clear(x)  ¬ On(b,x)) Spurious actions are possible: Move(B,C,C)

Example: air cargo transport:

Example: air cargo transport Init(At(C1, SFO)  At(C2,JFK)  At(P1,SFO)  At(P2,JFK)  Cargo(C1)  Cargo(C2)  Plane(P1)  Plane(P2)  Airport(JFK)  Airport(SFO)) Goal(At(C1,JFK)  At(C2,SFO)) Action(Load(c,p,a) PRECOND: At(c,a) At(p,a) Cargo(c) Plane(p) Airport(a) EFFECT: ¬ At(c,a) In(c,p)) Action(Unload(c,p,a) PRECOND: In(c,p) At(p,a) Cargo(c) Plane(p) Airport(a) EFFECT: At(c,a)  ¬ In(c,p)) Action(Fly(p,from,to) PRECOND: At(p,from) Plane(p) Airport(from) Airport(to) EFFECT: ¬ At(p,from)  At(p,to)) [Load(C1,P1,SFO), Fly(P1,SFO,JFK), Load(C2,P2,JFK), Fly(P2,JFK,SFO)]

Example: Spare tire problem:

Example: Spare tire problem Init(At(Flat, Axle)  At(Spare,trunk)) Goal(At(Spare,Axle)) Action(Remove(Spare,Trunk) PRECOND: At(Spare,Trunk) EFFECT: ¬ At(Spare,Trunk)  At(Spare,Ground)) Action(Remove(Flat,Axle) PRECOND: At(Flat,Axle) EFFECT: ¬ At(Flat,Axle)  At(Flat,Ground)) Action(PutOn(Spare,Axle) PRECOND: At(Spare,Groundp)  ¬ At(Flat,Axle) EFFECT: At(Spare,Axle)  ¬ At(Spare,Ground)) Action(LeaveOvernight PRECOND: EFFECT: ¬ At(Spare,Ground)  ¬ At(Spare,Axle)  ¬ At(Spare,trunk)  ¬ At(Flat,Ground)  ¬ At(Flat,Axle) ) This example goes beyond STRIPS: negative literal in pre-condition (ADL description)

Planning with state-space search:

Planning with state-space search Both forward and backward search possible Progression planners forward state-space search Consider the effect of all possible actions in a given state Regression planners backward state-space search To achieve a goal, what must have been true in the previous state.

Progression and regression:

Progression and regression

Progression algorithm:

Progression algorithm Formulation as state-space search problem: Initial state = initial state of the planning problem Literals not appearing are false Actions = those whose preconditions are satisfied Add positive effects, delete negative Goal test = does the state satisfy the goal Step cost = each action costs 1 No functions … any graph search that is complete is a complete planning algorithm. E.g. A* Inefficient: (1) irrelevant action problem (2) good heuristic required for efficient search

Regression algorithm:

Regression algorithm How to determine predecessors? What are the states from which applying a given action leads to the goal? Goal state = At(C1, B)  At(C2, B)  …  At(C20, B) Relevant action for first conjunct : Unload(C1,p,B) Works only if pre-conditions are satisfied . Previous state= In(C1, p)  At(p, B)  At(C2, B)  …  At(C20, B) Subgoal At(C1,B) should not be present in this state. Actions must not undo desired literals (consistent) Main advantage: only relevant actions are considered. Often much lower branching factor than forward search.

Regression algorithm :

Regression algorithm General process for predecessor construction Give a goal description G Let A be an action that is relevant and consistent The predecessors is as follows: Any positive effects of A that appear in G are deleted. Each precondition literal of A is added , unless it already appears. Any standard search algorithm can be added to perform the search. Termination when predecessor satisfied by initial state. In FO case, satisfaction might require a substitution.

Heuristics for state-space search:

Heuristics for state-space search Neither progression or regression are very efficient without a good heuristic. How many actions are needed to achieve the goal? Exact solution is NP hard, find a good estimate Two approaches to find admissible heuristic: The optimal solution to the relaxed problem. Remove all preconditions from actions The subgoal independence assumption: The cost of solving a conjunction of subgoals is approximated by the sum of the costs of solving the subproblems independently.

Partial-order planning:

Partial-order planning Progression and regression planning are totally ordered plan search forms. They cannot take advantage of problem decomposition. Decisions must be made on how to sequence actions on all the subproblems Least commitment strategy: Delay choice during search

Shoe example:

Shoe example Goal(RightShoeOn  LeftShoeOn) Init() Action(RightShoe, PRECOND: RightSockOn EFFECT: RightShoeOn) Action(RightSock, PRECOND: EFFECT: RightSockOn) Action(LeftShoe, PRECOND: LeftSockOn EFFECT: LeftShoeOn) Action(LeftSock, PRECOND: EFFECT: LeftSockOn) Planner: combine two action sequences (1)leftsock, leftshoe (2)rightsock, rightshoe

Partial-order planning(POP):

Partial-order planning(POP) Any planning algorithm that can place two actions into a plan without which comes first is a PO plan.

POP as a search problem:

POP as a search problem States are (mostly unfinished) plans. The empty plan contains only start and finish actions. Each plan has 4 components: A set of actions (steps of the plan) A set of ordering constraints: A < B (A before B) Cycles represent contradictions. A set of causal links The plan may not be extended by adding a new action C that conflicts with the causal link. (if the effect of C is ¬p and if C could come after A and before B) A set of open preconditions. If precondition is not achieved by action in the plan.

Example of final plan:

Example of final plan Actions={Rightsock, Rightshoe, Leftsock, Leftshoe, Start, Finish} Orderings={Rightsock < Rightshoe; Leftsock < Leftshoe} Links={Rightsock->Rightsockon -> Rightshoe, Leftsock->Leftsockon-> Leftshoe, Rightshoe->Rightshoeon->Finish, …} Open preconditions={}

POP as a search problem:

POP as a search problem A plan is consistent iff there are no cycles in the ordering constraints and no conflicts with the causal links. A consistent plan with no open preconditions is a solution . A partial order plan is executed by repeatedly choosing any of the possible next actions. This flexibility is a benefit in non-cooperative environments.

Solving POP:

Solving POP Assume propositional planning problems: The initial plan contains Start and Finish , the ordering constraint Start < Finish , no causal links, all the preconditions in Finish are open. Successor function : picks one open precondition p on an action B and generates a successor plan for every possible consistent way of choosing action A that achieves p . Test goal

Enforcing consistency:

Enforcing consistency When generating successor plan: The causal link A->p->B and the ordering constraint A < B is added to the plan. If A is new also add start < A and A < B to the plan Resolve conflicts between new causal link and all existing actions Resolve conflicts between action A (if new) and all existing causal links.

Process summary:

Process summary Operators on partial plans Add link from existing plan to open precondition. Add a step to fulfill an open condition. Order one step w.r.t another to remove possible conflicts Gradually move from incomplete/vague plans to complete/correct plans Backtrack if an open condition is unachievable or if a conflict is irresolvable.

Example: Spare tire problem:

Example: Spare tire problem Init(At(Flat, Axle)  At(Spare,trunk)) Goal(At(Spare,Axle)) Action(Remove(Spare,Trunk) PRECOND: At(Spare,Trunk) EFFECT: ¬ At(Spare,Trunk)  At(Spare,Ground)) Action(Remove(Flat,Axle) PRECOND: At(Flat,Axle) EFFECT: ¬ At(Flat,Axle)  At(Flat,Ground)) Action(PutOn(Spare,Axle) PRECOND: At(Spare,Groundp)  ¬ At(Flat,Axle) EFFECT: At(Spare,Axle)  ¬ Ar(Spare,Ground)) Action(LeaveOvernight PRECOND: EFFECT: ¬ At(Spare,Ground)  ¬ At(Spare,Axle)  ¬ At(Spare,trunk)  ¬ At(Flat,Ground)  ¬ At(Flat,Axle) )

Solving the problem:

Solving the problem Initial plan: Start with EFFECTS and Finish with PRECOND.

Solving the problem:

Solving the problem Initial plan: Start with EFFECTS and Finish with PRECOND. Pick an open precondition: At(Spare, Axle) Only PutOn(Spare, Axle) is applicable Add causal link: Add constraint : PutOn(Spare, Axle) < Finish

Solving the problem:

Solving the problem Pick an open precondition: At(Spare, Ground) Only Remove(Spare, Trunk) is applicable Add causal link: Add constraint : Remove(Spare, Trunk) < PutOn(Spare,Axle)

Solving the problem:

Solving the problem Pick an open precondition: ¬ At(Flat, Axle) LeaveOverNight is applicable conflict: LeaveOverNight also has the effect ¬ At(Spare,Ground) To resolve, add constraint : LeaveOverNight < Remove(Spare, Trunk)

Solving the problem:

Solving the problem Pick an open precondition: At(Spare, Trunk) Only Start is applicable Add causal link: Conflict: of causal link with effect At(Spare,Trunk) in LeaveOverNight No re-ordering solution possible. backtrack

Solving the problem:

Solving the problem Remove LeaveOverNight and causal links Add RemoveFlatAxle and finish

Some details …:

Some details … What happens when a first-order representation that includes variables is used? Complicates the process of detecting and resolving conflicts. Can be resolved by introducing inequality constraint. CSP’s most-constrained-variable constraint can be used for planning algorithms to select a PRECOND.

Planning graphs:

Planning graphs Used to achieve better heuristic estimates. A solution can also directly extracted using GRAPHPLAN. Consists of a sequence of levels that correspond to time steps in the plan. Level 0 is the initial state. Each level consists of a set of literals and a set of actions. Literals = all those that could be true at that time step, depending upon the actions executed at the preceding time step. Actions = all those actions that could have their preconditions satisfied at that time step, depending on which of the literals actually hold.

Planning graphs:

Planning graphs “Could”? Records only a restricted subset of possible negative interactions among actions. They work only for propositional problems. Example: Init(Have(Cake)) Goal(Have(Cake)  Eaten(Cake)) Action(Eat(Cake), PRECOND: Have(Cake) EFFECT: ¬Have(Cake)  Eaten(Cake)) Action(Bake(Cake), PRECOND: ¬ Have(Cake) EFFECT: Have(Cake))

Cake example:

Cake example Start at level S0 and determine action level A0 and next level S1. A0 >> all actions whose preconditions are satisfied in the previous level. Connect precond and effect of actions S0 --> S1 Inaction is represented by persistence actions . Level A0 contains the actions that could occur Conflicts between actions are represented by mutex links

Cake example:

Cake example Level S1 contains all literals that could result from picking any subset of actions in A0 Conflicts between literals that can not occur together (as a consequence of the selection action) are represented by mutex links. S1 defines multiple states and the mutex links are the constraints that define this set of states. Continue until two consecutive levels are identical: leveled off Or contain the same amount of literals (explanation follows later)

Cake example:

Cake example A mutex relation holds between two actions when: Inconsistent effects : one action negates the effect of another. Interference : one of the effects of one action is the negation of a precondition of the other. Competing needs : one of the preconditions of one action is mutually exclusive with the precondition of the other. A mutex relation holds between two literals when ( inconsistent support ): If one is the negation of the other OR if each possible action pair that could achieve the literals is mutex.

PG and heuristic estimation:

PG and heuristic estimation PG’s provide information about the problem A literal that does not appear in the final level of the graph cannot be achieved by any plan. Useful for backward search (cost = inf). Level of appearance can be used as cost estimate of achieving any goal literals = level cost . Small problem: several actions can occur Restrict to one action using serial PG (add mutex links between every pair of actions, except persistence actions). Cost of a conjunction of goals? Max-level, sum-level and set-level heuristics. PG is a relaxed problem.

The GRAPHPLAN Algorithm:

The GRAPHPLAN Algorithm How to extract a solution directly from the PG function GRAPHPLAN( problem ) return solution or failure graph  INITIAL-PLANNING-GRAPH( problem ) goals  GOALS[ problem ] loop do if goals all non-mutex in last level of graph then do solution  EXTRACT-SOLUTION( graph, goals, LENGTH (graph) ) if solution  failure then return solution else if NO-SOLUTION-POSSIBLE( graph ) then return failure graph  EXPAND-GRAPH( graph, problem )

Example: Spare tire problem:

Example: Spare tire problem Init(At(Flat, Axle)  At(Spare,trunk)) Goal(At(Spare,Axle)) Action(Remove(Spare,Trunk) PRECOND: At(Spare,Trunk) EFFECT: ¬ At(Spare,Trunk)  At(Spare,Ground)) Action(Remove(Flat,Axle) PRECOND: At(Flat,Axle) EFFECT: ¬ At(Flat,Axle)  At(Flat,Ground)) Action(PutOn(Spare,Axle) PRECOND: At(Spare,Groundp)  ¬ At(Flat,Axle) EFFECT: At(Spare,Axle)  ¬ At(Spare,Ground)) Action(LeaveOvernight PRECOND: EFFECT: ¬ At(Spare,Ground)  ¬ At(Spare,Axle)  ¬ At(Spare,trunk)  ¬ At(Flat,Ground)  ¬ At(Flat,Axle) ) This example goes beyond STRIPS: negative literal in pre-condition (ADL description)

GRAPHPLAN example:

GRAPHPLAN example Initially the plan consist of 5 literals from the initial state and the CWA literals (S0). Add actions whose preconditions are satisfied by EXPAND-GRAPH (A0) Also add persistence actions and mutex relations. Add the effects at level S1 Repeat until goal is in level Si

GRAPHPLAN example:

GRAPHPLAN example EXPAND-GRAPH also looks for mutex relations Inconsistent effects E.g. Remove(Spare, Trunk) and LeaveOverNight due to At(Spare,Ground) and not At(Spare, Ground) Interference E.g. Remove(Flat, Axle) and LeaveOverNight At(Flat, Axle) as PRECOND and not At(Flat,Axle) as EFFECT Competing needs E.g. PutOn(Spare,Axle) and Remove(Flat, Axle) due to At(Flat.Axle) and not At(Flat, Axle) Inconsistent support E.g. in S2, At(Spare,Axle) and At(Flat,Axle)

GRAPHPLAN example:

GRAPHPLAN example In S2, the goal literals exist and are not mutex with any other Solution might exist and EXTRACT-SOLUTION will try to find it EXTRACT-SOLUTION can use Boolean CSP to solve the problem or a search process: Initial state = last level of PG and goal goals of planning problem Actions = select any set of non-conflicting actions that cover the goals in the state Goal = reach level S0 such that all goals are satisfied Cost = 1 for each action.

GRAPHPLAN example:

GRAPHPLAN example Termination? YES PG are monotonically increasing or decreasing: Literals increase monotonically Actions increase monotonically Mutexes decrease monotonically Because of these properties and because there is a finite number of actions and literals, every PG will eventually level off !

Planning with propositional logic:

Planning with propositional logic Planning can be done by proving theorem in situation calculus. Here: test the satisfiability of a logical sentence: Sentence contains propositions for every action occurrence. A model will assign true to the actions that are part of the correct plan and false to the others An assignment that corresponds to an incorrect plan will not be a model because of inconsistency with the assertion that the goal is true. If the planning is unsolvable the sentence will be unsatisfiable.

SATPLAN algorithm:

SATPLAN algorithm function SATPLAN( problem, T max ) return solution or failure inputs: problem , a planning problem T max , an upper limit to the plan length for T= 0 to T max do cnf, mapping  TRANSLATE-TO_SAT( problem, T ) assignment  SAT-SOLVER( cnf ) if assignment is not null then return EXTRACT-SOLUTION( assignment, mapping ) return failure

cnf, mapping  TRANSLATE-TO_SAT(problem, T):

cnf, mapping  TRANSLATE-TO_SAT( problem, T ) Distinct propositions for assertions about each time step. Superscripts denote the time step At(P1,SFO) 0  At(P2,JFK) 0 No CWA thus specify which propositions are not true ¬At(P1,SFO) 0  ¬At(P2,JFK) 0 Unknown propositions are left unspecified. The goal is associated with a particular time-step But which one?

cnf, mapping  TRANSLATE-TO_SAT(problem, T):

cnf, mapping  TRANSLATE-TO_SAT( problem, T ) How to determine the time step where the goal will be reached? Start at T=0 Assert At(P1,SFO) 0  At(P2,JFK) 0 Failure .. Try T=1 Assert At(P1,SFO) 1  At(P2,JFK) 1 … Repeat this until some minimal path length is reached. Termination is ensured by T max

cnf, mapping  TRANSLATE-TO_SAT(problem, T):

cnf, mapping  TRANSLATE-TO_SAT( problem, T ) How to encode actions into PL? Propositional versions of successor-state axioms At(P1,JFK) 1  ( At(P1,JFK) 0  ¬ (Fly(P1,JFK,SFO) 0  At(P1,JFK) 0 ))  (Fly(P1,SFO,JFK) 0  At(P1,SFO) 0 ) Such an axiom is required for each plane, airport and time step If more airports add another way to travel than additional disjuncts are required Once all these axioms are in place, the satisfiability algorithm can start to find a plan.

assignment  SAT-SOLVER(cnf):

assignment  SAT-SOLVER( cnf ) Multiple models can be found They are NOT satisfactory: (for T=1) Fly(P1,SFO,JFK) 0  Fly(P1,JFK,SFO) 0  Fly(P2,JFK.SFO) 0 The second action is infeasible Yet the plan IS a model of the sentence Avoiding illegal actions: pre-condition axioms Fly(P1,SFO,JFK) 0  At(P1,JFK) Exactly one model now satisfies all the axioms where the goal is achieved at T=1 .

assignment  SAT-SOLVER(cnf):

assignment  SAT-SOLVER( cnf ) A plane can fly at two destinations at once They are NOT satisfactory: (for T=1) Fly(P1,SFO,JFK) 0  Fly(P2,JFK,SFO) 0  Fly(P2,JFK.LAX) 0 The second action is infeasible Yet the plan allows spurious relations Avoid spurious solutions: action-exclusion axioms ¬( Fly(P2,JFK,SFO) 0  Fly(P2,JFK,LAX)) Prevents simultaneous actions Lost of flexibility since plan becomes totally ordered : no actions are allowed to occur at the same time. Restrict exclusion to preconditions

Analysis of planning approach:

Analysis of planning approach Planning is an area of great interest within AI Search for solution Constructively prove a existence of solution Biggest problem is the combinatorial explosion in states. Efficient methods are under research E.g. divide-and-conquer

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