Three Phase fault in the middle of one of the lines :
Three Phase fault in the middle of one of the lines Pm = 0.8;E=1.17;V=1.0;
X1=0.65;X2=1.8;X3=0.8;
eacfault(Pm,E,V,X1,X2,X3)
Slide 4:
Pm = 0.8;E=1.17;V=1.0;
X1=0.65;X2=inf;X3=0.8;
eacfault(Pm,E,V,X1,X2,X3)
Fault Clearing Time set as 0.3sec :
Fault Clearing Time set as 0.3sec
Fault Clearing Time set as 0.5sec :
Fault Clearing Time set as 0.5sec
Slide 8:
Modeling of RLC series resonant circuit +
v(t) = 5 sin ?t
– i 10 ? 100 uF 0.01 H Writing KVL around the loop,
Slide 9:
Taking Laplace transform:
Slide 10:
Thus the current can be obtained from the voltage:
Slide 11:
Frequency verses current is plotted The input is 5sin(?t).