Data structure & algo 2

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Lecture 2 : 

Lecture 2 Insertion Sort and its analysis Chapter 2 Page 23 to 27

Insertion Sort Algorithm : 

Insertion Sort Algorithm INSERTION-SORT(A) For j ← 2 to length [A]     key ← A[j]     Put A[j] into the sorted sequence A[1 . . j -1]     i ← j -1     while i > 0 and A[i] > key A[i+1] ← A[i]             i ← i-1     A[i+1] ← key

Insertion Sort Continue : 

Insertion Sort Continue Input Size More input more time. Running Time The number of primitive operations or steps executed during a program execution is the running time of algorithm.

Analysis of Insertion Sort : 

Analysis of Insertion Sort INSERTION-SORT(A) for j ← 2 to n key ← A[ j ] Insert A[ j ] into the sorted sequence A[1 . . j -1] i ← j - 1 while i > 0 and A[i] > key A[i + 1] ← A[i] i ← i – 1 A[i + 1] ← key cost times c1 n c2 n-1 0 n-1 c4 n-1 c5 c6 c7 c8 n-1 4

Insertion Sort Continue : 

Insertion Sort Continue T(n) = c1n + c2(n – 1) + c4(n – 1) + c5 + c6 + c7 + c8(n – 1) Best Case Analysis For Best Case tj=1. Putting the value of tj=1 in the above equation we get T(n) = c1n + c2(n – 1) + c4(n – 1) + c5(n - 1) + c8(n – 1) = (c1 + c2 + c4 + c5 + c8)n – (c2 + c4 + c5 + c8) The above best case running time can be expressed as an+b. Thus it is a linear function of n. T(n) = Θ(n)

Insertion Sort Continue : 

Insertion Sort Continue T(n) = c1n + c2(n – 1) + c4(n – 1) + c5 + c6 + c7 + c8(n – 1) Worst Case Analysis For worst case tj = j. So = = and (Mathematical Proof) = = (Mathematical Proof) Putting these values in the above equation will give us the following T(n) = c1n +c2(n – 1) + c4(n –1) + c5 ((n(n+1)/2) –1) + c6(n(n-1)/2) + c7 (n(n-1)/2) + c8(n – 1) = (c5/2 + c6/2 + c7/2)n2 + (c1 + c2 + c4 + c5/2 – c6/2 – c7/2 + c8)n - (c2 + c4 + c5 + c8) The above worse case running time can be expressed as an2 + bn + c. So It is quadratic function of n T(n) = Θ(n2)

Insertion Sort Continue : 

Insertion Sort Continue Order Of Growth Ө If an algorithm has lower order of growth for its worst case analysis, then that algorithm is more efficient than another. The worst case running time for insertion sort is an2 + bn + c = an2 ( lower-order terms are insignificant for larger no. of inputs.) = Ө (n2) Insertion sort will run more quickly in the worst case than a Ө( n3) algorithm.