logging in or signing up heights and distances raushan_lal Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Copy Does not support media & animations WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 2457 Category: Education License: All Rights Reserved Like it (1) Dislike it (0) Added: October 18, 2011 This Presentation is Public Favorites: 4 Presentation Description heights and distances Comments Posting comment... Premium member Presentation Transcript Slide 1: HEIGHTS AND DISTANCES BY RAUSHAN LAL CLASS -10 TH ROLL NO. – 4. SUBMITTED TO – MISS NEHA MAMSlide 2: How the following diagram allows us to determine the height of the Eiffel Tower without actually having to climb it or the distance between the person and Eiffel Tower without actually walking . ? 45 o ? What you’re going to do next? Heights and DistancesSlide 3: In this situation , the distance or the heights can be founded by using mathematical techniques, which comes under a branch of ‘trigonometry’. The word ‘ trigonometry’ is derived from the Greek word ‘tri’ meaning three , ‘gon’ meaning sides and ‘metron’ meaning measures. Trigonometry is concerned with the relationship between the angles and sides of triangles . An understanding of these relationships enables unknown angles and sides to be calculated without recourse to direct measurement. Applications include finding heights/distances of objects.Slide 4: Early Beginning uses of trigonometry for determining heights and distancesSlide 5: Trigonometry ( Three- angle - measure ) The Great Pyramid (Cheops) at Giza, near Cairo, one of the 7 wonders of the ancient word. ( The only one still surviving ).This is the one of the earliest use of trigonometry. People use trigonometry for determining height of this pyramid.Slide 6: Trigonometry Sun’s rays casting shadows mid-afternoon Sun’s rays casting shadows late afternoon An early application of trigonometry was made by Thales on a visit to Egypt. He was surprised that no one could tell him the height of the 2000 year old Cheops pyramid. He used his knowledge of the relationship between the heights of objects and the length of their shadows to calculate the height for them. (This will later become the Tangent ratio.) Can you see what this relationship is, based on the drawings below? Thales of Miletus 640 – 546 B.C . The first Greek Mathematician. He predicted the Solar Eclipse of 585 BC. Similar Triangles Similar Triangles Thales may not have used similar triangles directly to solve the problem but he knew that the ratio of the vertical to horizontal sides of each triangle was constant and unchanging for different heights of the sun. Can you use the measurements shown above to find the height of Cheops? 6 ft 9 ft 720 ft h 480 ftSlide 7: Later, during the Golden Age of Athens (5C BC.), the philosophers and mathematicians were not particularly interested in the practical side of mathematics so trigonometry was not further developed. It was another 250 years or so, when the centre of learning had switched to Alexandria (current day Egypt) that the ideas behind trigonometry were more fully explored. The astronomer and mathematician, Hipparchus was the first person to construct tables of trigonometric ratios. Amongst his many notable achievements was his determination of the distance to the moon with an error of only 5%. He used the diameter of the Earth (previously calculated by Eratosthenes) together with angular measurements that had been taken during the total solar eclipse of March 190 BC. Hipparchus of Rhodes 190-120 BC Eratosthenes275 – 194 BC The library of Alexandria was the foremost seat of learning in the world and functioned like a university. The library contained 600 000 manuscripts.Slide 8: h 20 o 25 o x d Early Applications of Trigonometry Finding the height of a mountain/hill. Finding the distance to the moon. Constructing sundials to estimate the time from the sun’s shadow.Slide 9: Historically trigonometry was developed for work in Astronomy and Geography. Today it is used extensively in mathematics and many other areas of the sciences. Surveying Navigation Physics EngineeringSlide 10: 45 o Angle of elevation Line of sight Consider the figure. A C B In this figure, the line AC drawn from the eye of the student to the top of the tower is called the line of sight. The person is looking at the top of the tower. The angle BAC , so formed by line of sight with horizontal is called angle of elevation . Tower Horizontal level Angles of Elevation and Depression.Slide 11: Now consider the following figure. 45 o Line of sight Mountain Angle of depression A B C Object Horizontal level In this figure, the person standing on the top of the mountain is looking down at a flower pot. In this case , the line of sight is below the horizontal level. The angle so formed by the line of sight with the horizontal is called the angle of depression.Slide 12: 45 o Angle of elevation Line of sight A C B Tower Horizontal level Method of finding the heights or the distances Let us refer to figure of tower again. If you want to find the height of the tower i.e. BC without actually measuring it, what information do you need ?Slide 13: You would need to know the following: The distance AB which is the distance between tower and the person . The angle of elevation angle BAC . Assuming that the above two conditions are given then how can we determine the height of the height of the tower ? In ∆ABC, the side BC is the opposite side in relation to the known angle A. Now, which of the trigonometric ratios can we use ? Which one of them has the two values that we have and the one we need to determine ? Our search narrows down to using either tan A or cot A, as these ratios involve AB and BC. There fore, tan A = BC/AB or cot A = AB/BC , which on solving would give us BC i.e., the height of the tower .Slide 14: Some Applications of trigonometry based on finding heights and distanceSlide 15: 45 o 28.5m A B C Here we have to find the height of the school. Here BC = 28.5 m and AC i.e., the height of the school = tan 45 = AC/BC i.e., 1 = AC/28.5 Therefore , AC = 28.5m So the height of the school is 28.5 m.Slide 16: 60 o 3.7m B A C Here we have to find the length of the ladder in the below figure and also how far is the foot of the ladder from the house ? (here take √3 = 1.73m) Now, can you think trigonometric ratios should we consider ? It should be sin 60 So, BC/AB = sin 60 or 3.7/AB = √3/2 Therefore BC = 3.7 x 2/√3 Hence length of the ladder is 4.28m Now BC/AC = cot 60 = 1/√3 i.e., AC = 3.7/√3 = 2.14m (approx) Therefore the foot of the ladder from the house is 2.14m.Slide 17: 45 o 30 o P D A B Here we need to find the height of the lighthouse above the mountain . Given that AB = 10 m. (here take √3 =1.732). 10 mSlide 18: Since we know the height of the mountain is AB so we consider the right ∆PAB. We have tan 30 = AB/AP i.e., 1/ √3 = 10/AP therefore AP = 10√3m so the distance of the building = 10√3m = 17.32m Let us suppose DB = (10+ x )m now in right ∆PAD tan 45 = AD/AP = 10+ x/ 10√3 therefore 1 = 10+ x/ 10√3 i.e., x = 10( √3-1) =7.32. So, the length of the flagstaff is 7.32mSlide 19: Summary: The line of sight is the line drawn from the eye of the observer to the point in the object viewed by the observer. The angle of elevation of an object viewed, is the angle formed by the line of sight with the horizontal when it is above the horizontal level, i.e., the case when we raise our head to look at the object. The angle of depression of an object viewed, is the angle formed by the line of sight with the horizontal when it is below the horizontal level , i.e., the case when we lower our the head to look at the object. The height or length of an object or the distance between two distant objects can be determined with the help of trigonometric ratios .Slide 20: THE END You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.