logging in or signing up Topic6-3ArcsChords rafranz11 Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 23 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: April 12, 2011 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Topic 6-3 Arcs & Chords : Topic 6-3 Arcs & Chords Rafranz Dixon EHS Geometry What is a CHORD? : What is a CHORD? A segment with two endpoints on the circle Chord Chord Theorem 1 : Theorem 1 2 minor arcs are congruent if and only if their corresponding chords are congruent. Click to Investigate Slide 4: & AB & CD ( ( Degrees of full circle= 360 Since AB and CD are equal and the only two unknown arcs, let both arcs be X. x x 2x + 240 = 360 Solve for x and you are done!!! X = 60 Slide 5: Comparing degrees with arc lengths onlY Add 50 + 20 to get the degree of the arc corresponding with chord PS. Since Arc PS = Arc QR Chords PS and QR are equal. PS = 12 so QR = 12 Slide 6: Comparing degrees with arc lengths onlY Degrees of full circle= 360 Add the degrees you have so far, then subtract from 360 Compare degrees to the other arc degrees Your answer will be the length with the same arc degree. Theorem 2 : Theorem 2 In a circle, if the diameter or a radius is perpendicular to a chord, then it bisects the chord and its arc. Click to Investigate Slide 8: 1st Step ALWAYS - Label Information Cross at 90° 12 13 Right Triangle Pythagorean THeorem 1 Radius AD=13, AE= 12 so 13-12 = 1 13 AC = radius 13 AB = radius 5 5 Radius = perpendicular bisector 10 Add 5 + 5 Press these now Slide 9: 3 letters =Major arc 220° 140° 360 – 220 = 140 140° Central angle of arc CB 70° ½ angle CAB 70° ½ arc CB Press Smiley faces for answers Slide 10: Chord 1st step, Find important information Whole chord = 12, each half = 6 6 radius 8 10 30 – 60 – 90 triangles x 2x 2x = 6 x = 3 3 120° Theorem 3 : Theorem 3 Two chords are congruent if and only if they are equidistant from the center. Click to Investigate Slide 12: 8 16 3 5 4 Determine if the distances From the center to the chords Are the same 4 3 3 6 Press for each step of example 9 Begin Homework!!!! : Begin Homework!!!! Take Your Time…Think Hard You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
Topic6-3ArcsChords rafranz11 Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 23 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: April 12, 2011 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Topic 6-3 Arcs & Chords : Topic 6-3 Arcs & Chords Rafranz Dixon EHS Geometry What is a CHORD? : What is a CHORD? A segment with two endpoints on the circle Chord Chord Theorem 1 : Theorem 1 2 minor arcs are congruent if and only if their corresponding chords are congruent. Click to Investigate Slide 4: & AB & CD ( ( Degrees of full circle= 360 Since AB and CD are equal and the only two unknown arcs, let both arcs be X. x x 2x + 240 = 360 Solve for x and you are done!!! X = 60 Slide 5: Comparing degrees with arc lengths onlY Add 50 + 20 to get the degree of the arc corresponding with chord PS. Since Arc PS = Arc QR Chords PS and QR are equal. PS = 12 so QR = 12 Slide 6: Comparing degrees with arc lengths onlY Degrees of full circle= 360 Add the degrees you have so far, then subtract from 360 Compare degrees to the other arc degrees Your answer will be the length with the same arc degree. Theorem 2 : Theorem 2 In a circle, if the diameter or a radius is perpendicular to a chord, then it bisects the chord and its arc. Click to Investigate Slide 8: 1st Step ALWAYS - Label Information Cross at 90° 12 13 Right Triangle Pythagorean THeorem 1 Radius AD=13, AE= 12 so 13-12 = 1 13 AC = radius 13 AB = radius 5 5 Radius = perpendicular bisector 10 Add 5 + 5 Press these now Slide 9: 3 letters =Major arc 220° 140° 360 – 220 = 140 140° Central angle of arc CB 70° ½ angle CAB 70° ½ arc CB Press Smiley faces for answers Slide 10: Chord 1st step, Find important information Whole chord = 12, each half = 6 6 radius 8 10 30 – 60 – 90 triangles x 2x 2x = 6 x = 3 3 120° Theorem 3 : Theorem 3 Two chords are congruent if and only if they are equidistant from the center. Click to Investigate Slide 12: 8 16 3 5 4 Determine if the distances From the center to the chords Are the same 4 3 3 6 Press for each step of example 9 Begin Homework!!!! : Begin Homework!!!! Take Your Time…Think Hard