QUESTION 5:- 1 (ix) (cosec A – sin A) (sec A – cos A) = —-------------------- tan A + cot A:
QUESTION 5:- 1 (ix) (cosec A – sin A) (sec A – cos A) = —-------------------- tan A + cot A
(1 + tan2 A ) = 1 – tan A 2 = tan2 A(1 + cot2 A ) 1 – cot A:
(1 + tan2 A ) = 1 – tan A 2 = tan2 A (1 + cot2 A ) 1 – cot A
slide4:
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