logging in or signing up Algebra 2 TEST 7.1-7.5 PRACTICE SOLUTION mrpetersen Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Dynamic Copy Does not support media & animations Automatically changes to Flash or non-Flash embed WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 897 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: April 08, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Algebra 2 TEST 7.1–7.5PRACTICE : Algebra 2 TEST 7.1–7.5PRACTICE Solutions! 1 : 1 Find all the real-number roots. Note: There are two square roots of 0.16, namely 0.4 and –0.4. However, the radical sign is the principle root—the positive root whenever there is a choice! 2 : 2 Find all the real-number roots. No real solution. Neither a positive number squared nor a negative number squared gives a negative. There is no real number root to a negative number like –81. 3 : 3 Find all the real-number roots. On your calculator type: 4 : 4 Simplify each radical expression. Use absolute value symbols if needed. Note: If a radical has an even index (here 4) then the absolute value bars are needed. However, since both 2 and a2 are always positive, they may be removed from the absolute value bars. 5 : 5 Simplify each radical expression. Use absolute value symbols if needed. Note: Cube roots have only one answer. There is no need to choose between a positive and a negative value. Therefore, no absolute value bars should be used here. 6 : 6 Simplify each radical expression. Use absolute value symbols if needed. 7 : 7 Multiply and simplify if possible. 8 : 8 Multiply and simplify if possible. There are no real number square roots of a negative number (here –6). This problem has no real number solution. 9 : 9 Multiply and simplify if possible. 10 : 10 Multiply. 11 : 11 Multiply. 12 : 12 Multiply. Note: Usually we would FOIL the first line. With conjugates the outside and inside terms always cancel. FOIL reduces to simply FL. 13 : 13 Simplify. Assume that all variables are positive. 14 : 14 Simplify. Assume that all variables are positive. Note: If we “assume that the variables are positive” then absolute value bars are not needed. 15 : 15 Multiply and simplify. Assume that all variables are positive. 16 : 16 Multiply and simplify. Assume that all variables are positive. 17 : 17 Divide and simplify. 18 : 18 Divide and simplify. 19 : 19 Divide and simplify. Assume that all variable are positive. 20 : 20 Divide and simplify. Assume that all variable are positive. 21 : 21 Rationalize the denominator of the expression. Assume that all variables are positive. Comment: This is a killer problem! 22 : 22 Rationalize the denominator of the expression. Assume that all variables are positive. 23 : 23 Rationalize the denominator of the expression. Assume that all variables are positive. Note: FOIL on top; FL on bottom! 24 : 24 Add or subtract if possible. Simplify all answers. 25 : 25 Add or subtract if possible. Simplify all answers. Note: This problem cannot be simplified any further. The radicands are different. 26 : 26 Add or subtract if possible. Simplify all answers. 27 : 27 Simplify. 28 : 28 Simplify. 29 : 29 Simplify. 30 : 30 Simplify. 31 : 31 Write the following in radical form. 32 : 32 Write the following in radical form. 33 : 33 Write in simplest form. 34 : 34 Solve and check for extraneous roots. 35 (method 1) : 35 (method 1) Solve and check for extraneous roots. Note: Both answers check! 35 (method 2) : 35 (method 2) Solve and check for extraneous roots. Note: Both answers check! 36 : 36 Solve and check for extraneous roots. Note: –6 fails in the original. Extraneous! You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
Algebra 2 TEST 7.1-7.5 PRACTICE SOLUTION mrpetersen Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Dynamic Copy Does not support media & animations Automatically changes to Flash or non-Flash embed WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 897 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: April 08, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Algebra 2 TEST 7.1–7.5PRACTICE : Algebra 2 TEST 7.1–7.5PRACTICE Solutions! 1 : 1 Find all the real-number roots. Note: There are two square roots of 0.16, namely 0.4 and –0.4. However, the radical sign is the principle root—the positive root whenever there is a choice! 2 : 2 Find all the real-number roots. No real solution. Neither a positive number squared nor a negative number squared gives a negative. There is no real number root to a negative number like –81. 3 : 3 Find all the real-number roots. On your calculator type: 4 : 4 Simplify each radical expression. Use absolute value symbols if needed. Note: If a radical has an even index (here 4) then the absolute value bars are needed. However, since both 2 and a2 are always positive, they may be removed from the absolute value bars. 5 : 5 Simplify each radical expression. Use absolute value symbols if needed. Note: Cube roots have only one answer. There is no need to choose between a positive and a negative value. Therefore, no absolute value bars should be used here. 6 : 6 Simplify each radical expression. Use absolute value symbols if needed. 7 : 7 Multiply and simplify if possible. 8 : 8 Multiply and simplify if possible. There are no real number square roots of a negative number (here –6). This problem has no real number solution. 9 : 9 Multiply and simplify if possible. 10 : 10 Multiply. 11 : 11 Multiply. 12 : 12 Multiply. Note: Usually we would FOIL the first line. With conjugates the outside and inside terms always cancel. FOIL reduces to simply FL. 13 : 13 Simplify. Assume that all variables are positive. 14 : 14 Simplify. Assume that all variables are positive. Note: If we “assume that the variables are positive” then absolute value bars are not needed. 15 : 15 Multiply and simplify. Assume that all variables are positive. 16 : 16 Multiply and simplify. Assume that all variables are positive. 17 : 17 Divide and simplify. 18 : 18 Divide and simplify. 19 : 19 Divide and simplify. Assume that all variable are positive. 20 : 20 Divide and simplify. Assume that all variable are positive. 21 : 21 Rationalize the denominator of the expression. Assume that all variables are positive. Comment: This is a killer problem! 22 : 22 Rationalize the denominator of the expression. Assume that all variables are positive. 23 : 23 Rationalize the denominator of the expression. Assume that all variables are positive. Note: FOIL on top; FL on bottom! 24 : 24 Add or subtract if possible. Simplify all answers. 25 : 25 Add or subtract if possible. Simplify all answers. Note: This problem cannot be simplified any further. The radicands are different. 26 : 26 Add or subtract if possible. Simplify all answers. 27 : 27 Simplify. 28 : 28 Simplify. 29 : 29 Simplify. 30 : 30 Simplify. 31 : 31 Write the following in radical form. 32 : 32 Write the following in radical form. 33 : 33 Write in simplest form. 34 : 34 Solve and check for extraneous roots. 35 (method 1) : 35 (method 1) Solve and check for extraneous roots. Note: Both answers check! 35 (method 2) : 35 (method 2) Solve and check for extraneous roots. Note: Both answers check! 36 : 36 Solve and check for extraneous roots. Note: –6 fails in the original. Extraneous!