logging in or signing up Area of a rectangular paths loloosingh Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Dynamic Copy Does not support media & animations Automatically changes to Flash or non-Flash embed WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 1276 Category: Science & Tech.. License: All Rights Reserved Like it (0) Dislike it (0) Added: November 07, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Area of a rectangular path. : Area of a rectangular path. BY V JOIS TGT(Maths) K.V.No.1 Mangalore. Area of a rectangle=length x breadthArea of a square=side x side : Area of a rectangle=length x breadthArea of a square=side x side Rectangular paths are generally found around (outside or inside) a rectangle or in the form of central paths. Finding area of paths. : Finding area of paths. Example:A garden is 90m long and 75m broad.A path 5m wide is to be built outside around it.Find the area of the path. Solution:Let us represent the garden by the rectangle PQRS and the path around it by the shaded region. Slide 4: A B C D P Q R S 100M 90M 75M 85M Now AB=DC=(90+5+5)M=100M AD=BC=(75+5+5)M=85M Area of the path=Area of the rectangle ABCD- Area of the rectangle PQRS=100 X 85-90 X75 Sq m=(8500- 6750)Sq m=1750sq m : Area of the path=Area of the rectangle ABCD- Area of the rectangle PQRS=100 X 85-90 X75 Sq m=(8500- 6750)Sq m=1750sq m Thus, the area of the path is 1750sq m Example:Two cross roads each of width 5m run at right angles through the centre of a rectangular park of length 700m and breadth 300m parallel to its sides.Find the area of the roads.Also,find the cost of constructing roads at the rate of Rs105 per sq.m . : Example:Two cross roads each of width 5m run at right angles through the centre of a rectangular park of length 700m and breadth 300m parallel to its sides.Find the area of the roads.Also,find the cost of constructing roads at the rate of Rs105 per sq.m . Solution:Let us represent the rectangular park by the rectangle ABCD and the two cross roads by the rectangles EFGH and PQRS. Slide 7: A B C D F G H L M N O 5M 5M 700M 300M P Q R S E Now,Area of the roads=Area of EFGH+ Area of PQRS-Area of LMNO=(300X5+700X5-5X5)Sq m=(1500+3500-25)Sq m=4975 Sq m : Now,Area of the roads=Area of EFGH+ Area of PQRS-Area of LMNO=(300X5+700X5-5X5)Sq m=(1500+3500-25)Sq m=4975 Sq m Cost of constructing roads at the rate of Rs105 per Sq m=Rs4975x105 =Rs522375. Work out the following problems : Work out the following problems 1. A path 5m wide runs along inside a square park of side 100m. Find the area of the path. You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
Area of a rectangular paths loloosingh Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: Embed: Flash iPad Dynamic Copy Does not support media & animations Automatically changes to Flash or non-Flash embed WordPress Embed Customize Embed URL: Copy Thumbnail: Copy The presentation is successfully added In Your Favorites. Views: 1276 Category: Science & Tech.. License: All Rights Reserved Like it (0) Dislike it (0) Added: November 07, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Area of a rectangular path. : Area of a rectangular path. BY V JOIS TGT(Maths) K.V.No.1 Mangalore. Area of a rectangle=length x breadthArea of a square=side x side : Area of a rectangle=length x breadthArea of a square=side x side Rectangular paths are generally found around (outside or inside) a rectangle or in the form of central paths. Finding area of paths. : Finding area of paths. Example:A garden is 90m long and 75m broad.A path 5m wide is to be built outside around it.Find the area of the path. Solution:Let us represent the garden by the rectangle PQRS and the path around it by the shaded region. Slide 4: A B C D P Q R S 100M 90M 75M 85M Now AB=DC=(90+5+5)M=100M AD=BC=(75+5+5)M=85M Area of the path=Area of the rectangle ABCD- Area of the rectangle PQRS=100 X 85-90 X75 Sq m=(8500- 6750)Sq m=1750sq m : Area of the path=Area of the rectangle ABCD- Area of the rectangle PQRS=100 X 85-90 X75 Sq m=(8500- 6750)Sq m=1750sq m Thus, the area of the path is 1750sq m Example:Two cross roads each of width 5m run at right angles through the centre of a rectangular park of length 700m and breadth 300m parallel to its sides.Find the area of the roads.Also,find the cost of constructing roads at the rate of Rs105 per sq.m . : Example:Two cross roads each of width 5m run at right angles through the centre of a rectangular park of length 700m and breadth 300m parallel to its sides.Find the area of the roads.Also,find the cost of constructing roads at the rate of Rs105 per sq.m . Solution:Let us represent the rectangular park by the rectangle ABCD and the two cross roads by the rectangles EFGH and PQRS. Slide 7: A B C D F G H L M N O 5M 5M 700M 300M P Q R S E Now,Area of the roads=Area of EFGH+ Area of PQRS-Area of LMNO=(300X5+700X5-5X5)Sq m=(1500+3500-25)Sq m=4975 Sq m : Now,Area of the roads=Area of EFGH+ Area of PQRS-Area of LMNO=(300X5+700X5-5X5)Sq m=(1500+3500-25)Sq m=4975 Sq m Cost of constructing roads at the rate of Rs105 per Sq m=Rs4975x105 =Rs522375. Work out the following problems : Work out the following problems 1. A path 5m wide runs along inside a square park of side 100m. Find the area of the path.