logging in or signing up algebra 2 8.6 jwaychoff Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 43 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: July 20, 2010 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: Solve the equation. Bell Ringer WarmUps –15x + 4 -6 = x Slide 3: EXAMPLE 1 Solve a rational equation by cross multiplying Solve: Write original equation. 3(4x + 5) = 9(x + 1) Cross multiply. 12x + 15 = 9x + 9 Distributive property 3x + 15 = 9 Subtract 9x from each side. 3x = – 6 Subtract 15 from each side. x = – 2 Divide each side by 3. Slide 4: EXAMPLE 2 Write and use a rational model x is the amount of silver added. 7.5(15 + x) = 100(0.2)(15) Cross multiply. 112.5 + 7.5x = 300 Simplify. 7.5x = 187.5 Subtract 112.5 from each side. x = 25 Divide each side by 7.5. Slide 5: GUIDED PRACTICE for Examples 1 and 2 Write original equation. 3(x – 7) = 2(5x ) Cross multiply. 3x – 21 = 10x Distributive property – 7x – 21 = 0 Subtract 10x from each side. – 7x = 21 Subtract 21 from each side. x = – 3 Divide each side by 7. SOLUTION Slide 6: GUIDED PRACTICE for Examples 1 and 2 Write original equation. – 4(x – 3) = 5(x + 3) Cross multiply. Distributive property – 9x + 12 = 15 Subtract 5x from each side. Subtract 12 from each side. Divide each side by 9. – 4x + 12 = 5x + 15 – 9x = 3 SOLUTION Slide 7: GUIDED PRACTICE for Examples 1 and 2 Write original equation. 1(11x + 8) = x(2x + 5) Cross multiply. Distributive property 2x2 – 6x2 +8 = 0 Subtract 2x2 , and 5 from each side. 11x + 8 = 2x2 + 5x x2 – 3x2 +4= 0 (x – 4)(x + 1) = 0 x = 4 , x = –1 Slide 8: EXAMPLE 3 Standardized Test Practice SOLUTION Write original equation. Multiply each side by the LCD, 4x. 20 + 7x = –36 Simplify. 7x = – 56 Subtract 20 from each side. x = – 8 Divide each side by 7. ) Slide 9: EXAMPLE 4 Solve a rational equation with two solutions Solve: Write original equation. Multiply each side by the LCD, x(x–5). x(x –5) – 8x = 3(x – 5) Simplify. x2 – 5x – 8x = 3x – 15 Simplify. x2 – 16x +15 = 0 Write in standard form. (x – 1)(x – 15) = 0 Factor. x = 1 or x = 15 Zero product property The solutions are 1 and 15. Check these in the original equation. Slide 10: GUIDED PRACTICE for Examples 3, 4 and 5 Solve the equation by using the LCD. Check for extraneous solutions. 7x + 6 = 6x x = – 6 Slide 11: GUIDED PRACTICE for Examples 3, 4 and 5 6 + 4x = 6x 6 = 2x x = 3 Homework 8.6 : Homework 8.6 Pages: 593 – 595 Exs. 4, 8, 12, 14, 18, 22, 24, 28, 39, 40 You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
algebra 2 8.6 jwaychoff Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 43 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: July 20, 2010 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: Solve the equation. Bell Ringer WarmUps –15x + 4 -6 = x Slide 3: EXAMPLE 1 Solve a rational equation by cross multiplying Solve: Write original equation. 3(4x + 5) = 9(x + 1) Cross multiply. 12x + 15 = 9x + 9 Distributive property 3x + 15 = 9 Subtract 9x from each side. 3x = – 6 Subtract 15 from each side. x = – 2 Divide each side by 3. Slide 4: EXAMPLE 2 Write and use a rational model x is the amount of silver added. 7.5(15 + x) = 100(0.2)(15) Cross multiply. 112.5 + 7.5x = 300 Simplify. 7.5x = 187.5 Subtract 112.5 from each side. x = 25 Divide each side by 7.5. Slide 5: GUIDED PRACTICE for Examples 1 and 2 Write original equation. 3(x – 7) = 2(5x ) Cross multiply. 3x – 21 = 10x Distributive property – 7x – 21 = 0 Subtract 10x from each side. – 7x = 21 Subtract 21 from each side. x = – 3 Divide each side by 7. SOLUTION Slide 6: GUIDED PRACTICE for Examples 1 and 2 Write original equation. – 4(x – 3) = 5(x + 3) Cross multiply. Distributive property – 9x + 12 = 15 Subtract 5x from each side. Subtract 12 from each side. Divide each side by 9. – 4x + 12 = 5x + 15 – 9x = 3 SOLUTION Slide 7: GUIDED PRACTICE for Examples 1 and 2 Write original equation. 1(11x + 8) = x(2x + 5) Cross multiply. Distributive property 2x2 – 6x2 +8 = 0 Subtract 2x2 , and 5 from each side. 11x + 8 = 2x2 + 5x x2 – 3x2 +4= 0 (x – 4)(x + 1) = 0 x = 4 , x = –1 Slide 8: EXAMPLE 3 Standardized Test Practice SOLUTION Write original equation. Multiply each side by the LCD, 4x. 20 + 7x = –36 Simplify. 7x = – 56 Subtract 20 from each side. x = – 8 Divide each side by 7. ) Slide 9: EXAMPLE 4 Solve a rational equation with two solutions Solve: Write original equation. Multiply each side by the LCD, x(x–5). x(x –5) – 8x = 3(x – 5) Simplify. x2 – 5x – 8x = 3x – 15 Simplify. x2 – 16x +15 = 0 Write in standard form. (x – 1)(x – 15) = 0 Factor. x = 1 or x = 15 Zero product property The solutions are 1 and 15. Check these in the original equation. Slide 10: GUIDED PRACTICE for Examples 3, 4 and 5 Solve the equation by using the LCD. Check for extraneous solutions. 7x + 6 = 6x x = – 6 Slide 11: GUIDED PRACTICE for Examples 3, 4 and 5 6 + 4x = 6x 6 = 2x x = 3 Homework 8.6 : Homework 8.6 Pages: 593 – 595 Exs. 4, 8, 12, 14, 18, 22, 24, 28, 39, 40