electronic-and-communication-engineering-ese

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ESE 2020 - Electronic and Communication Engineering ESE Topicwise Conventional Solved Paper 2 https://iesmasterpublications.com/ese-electronic-and-communication-engineering-ese-topicwise-conventional-solved-paper-2

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1998-2019 ELECTRONICS COMMUNICATION ENGINEERING ESE TOPICWISE CONVENTIONAL SOLVED PAPER-II Office: F-126 Lower Basement Katwaria Sarai New Delhi-110 016 Phone: 011-2652 2064  Mobile: 81309 09220 97118 53908 Email: info.publicationsiesmaster.org infoiesmaster.org Web: iesmasterpublications.com iesmaster.org

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First Edition : 2018 Second Edition : 2019 Typeset at : IES Master Publication New Delhi-110016 IES MASTER PUBLICA TION F-126 Lower Basement Katwaria Sarai New Delhi-110016 Phone : 011-26522064 Mobile : 8130909220 9711853908 E-mail : info.publicationsiesmaster.org Web : iesmasterpublications.com All rights reserved. Copyright © 2019 by IES MASTER Publication. No part of this booklet may be reproduced or distributed in any form or by any means electronic mechanical photocopying recording or otherwise or stored in a database or retrieval system without the prior permission of IES MASTER Publication New Delhi. Violates are liable to be legally prosecuted.

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PREFACE Engineering Services Exam ESE is one of most coveted exams written by engineering students aspiring for reputed posts in the various departments of the Government of India. ESE is conducted by the Union Public Services Commission UPSC and therefore the standards to clear this exam too are very high. To clear the ESE a candidate needs to clear three stages - ESE Prelims ESE Mains and Personality Test. It is not mere hard work that helps a student succeed in an examination like ESE that witnesses lakhs of aspirants competing neck to neck to move one step closer to their dream job. It is hard work along with smart work that allows an ESE aspirant to fulfil his dream. After detailed interaction with students preparing for ESE IES Master has come up with this book which is a one-stop solution for engineering students aspiring to crack this most prestigious engineering exam. The book includes previous years solved conventional questions segregated subject-wise along with detailed explanation. This book will also help ESE aspirants get an idea about the pattern and weightage of questions asked in ESE. IES Master feels immense pride in bringing out this book with utmost care to build upon the exam preparedness of a student up to the UPSC standards. The credit for flawless preparation of this book goes to the entire team of IES Master Publication. Teachers students and professional engineers are welcome to share their suggestions to make this book more valuable. IES Master Publication New Delhi

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CONTENTS 1. ANALOG DIGITAL COMMUNICATION SYSTEM ................................. 01 – 71 2. CONTROL SYSTEM .............................................................................. 72 – 185 3. COMPUTER ORGANIZATION ARCHITECTURE ............................... 186 – 214 4. ELECTROMAGNETIC FIELD THEORY ................................................ 215 – 301 5. ADVANCE ELECTRONICS ................................................................... 302 – 315 6. ADVANCE COMMUNICATION SYSTEM .............................................. 316 – 366 7. SIGNAL SYSTEM ............................................................................ 367 – 425 8. MICROPROCESSOR ........................................................................... 426 – 460

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1. Random Variables and Noise ..................................................................... 02-12 2. Analog Communication System .................................................................. 13-29 3. Digital Communication System ................................................................... 30-55 4. Fundamentals of Information Theory .......................................................... 56-71 UNIT 1 ANALOG AND DIGITAL COMMUNICATION SYSTEM SYLLABUS Random signals noise probability theory information theory Analog versus digital communication applications Systems-AM FM transmitters/receivers theory/practice/standards SNR comparison Digital communication basics: Sampling qunatizing coding PCM DPCM multiplexing-audio/video Digital modulation: ASK FSK PSK: Multiple access: TDMA FDMA CDMA Optical communication: fibre optics theory practice/standards. CONTENTS

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Q–1: A two stage amplifier has the following parameters : First stage Second stage Voltage gain 12 20 Input resistance 500 ohms 80 K ohms Equivalent Noise Resistance 1500 ohms 10 K ohms Output Resistance 25 K ohms 1 M ohms Calculate : i the equivalent noise resistance of the two stage amplifier ii the noise figure of the amplifier if it is driven by a generator with output impedance 50 ohms. 15 Marks ESE–1998 Sol. Given : The voltage gain of first stage A 1 12 The voltage gain of second stage A 2 20 Input resistance for first stage R i1  500 Input resistance for second stage R i2 10 K Now R 1 R i1 + R n1 Noise resistance is in series with input resistance R 1 1500 + 500 R 1  2000 Also R 2   01 i2 n2 R R R   output resistance of first stage is parallel to input resistance of 2 nd stage + equivalent noise resistance of 2 nd stage R 2     10K 25K 80K R 2         25 80 K 10 105 R 2 29.04 K Again      3 02 R R 1M 1000K Now equivalent input noise resistance is given as R eq   3 2 1 2 2 2 1 1 2 R R R A A A           3 6 2 2 2 29.04 10 10 2000 20 12 12 1 Random Variables and Noise Chapter

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ESE Topicwise Conventional Solved Paper-II 3 IES MASTER Publication Electronics Communication Engineering    29040 1000 2000 144 144 4 R eq  2219.1 Noise figure given by F        1 eq a R 1 R ...1 When 1 eq eq i1 R R R     1719.1 2219.1 500    R a output resistance of generator  50 Hence from 1 F   1719.1 1 35.38 50 F 35.38 or 15.48 dB F in dB 10log 10 F Q–2: Show that the input-to-output SNR gain of a matched filter depends on the product of the input signal duration and the noise bandwidth. 10 Marks ESE–2002 Sol. Impulse response of matched filter is ht   S T t  T Time period of st Noise power at output of the filter is given as P n   2 df H f 2      where 2  Noise power spectral density at output filter. . Now   2 0 S T     2 2 fT i H S .e df f f        Signal to noise ratio at the output is given as SNR o/p       2 j2 fT i 2 H S e df f f df H f 2                     2 i df E Energy of the signal S f          o/p SNR  2E    o/p max SNR 2E        ...i Now the input signal to noise ratio is given as S i   T 2 i 0 1 E S dt t T T         N i     .B 2B 2          B Noise bandwidth

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Analog and Digital Communication System 4 SNR i i i E S BT N         ...ii Now from i and ii     o/p i/p SNR SNR 2E BT 2BT E          o/p i/p SNR SNR 2BT Q–3: An amplifier has a noise figure of 4 dB a bandwidth of 500 kHz and an input resistance of 50 . Calculate the input signal voltage needed to yield an output SNR 1 when the amplifier is connected to a signal source of 50  at 290 K. 8 Marks ESE–2006 Sol. Given that for amplifier Noise figure   n dB 4dB F  Bandwidth n B 5000 kHz  and   0 SNR 0 0 S 1 N  Amp R 50 S  + – V S V i R in R in 50  Let S i be the input signal power and N i be input noise power then S i   2 i in V R or S i 2 in 2 s in s in R 1 V R R R        2 2 s 1 50 .V 50 50 50         2 s V 200        V s i S 200  ...i Since Noise figure       in i n out SNR SNR F 1 SNR     i i i S SNR N   S i n i F N  n 0 n F KT B  ...ii Where K Boltzman’s constant 23 1.38 10   B n Receiver bandwidth 3 500 10 Hz  T o Temperature 290 K    n dB F   10 n 10log F or 4   10 n 10log F or F n   0.4 2.512 10  Hence from eq. ii S i 23 3 2.512 1.38 10 290 500 10      

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