logging in or signing up Mole to Mole Stoichiometry grazianir Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 685 Category: Entertainment License: All Rights Reserved Like it (1) Dislike it (0) Added: October 23, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: Stoichiometry The study of amounts in a chemical reaction Root words: Stoicheion – element Metron - measure Slide 2: Stoichiometry Steps Balance Chemical Equation Determine mole ratios Pick the correct mole ratio and multiply it by the moles of substance given. Mole Ratio : Mole Ratio A mole ratio is basically a fraction of the moles of one substance in a chemical reaction over the moles of another substance in the equation. Mole Ratios : Mole Ratios 2 H2(g) + O2(g) 2 H2O(l) Slide 5: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Slide 6: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 1: Write the number and unit given. Slide 7: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 2: Multiply by correct mole ratio to cancel out mole N2 and to get mole NH3 on top. x = Slide 8: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 3: Cancel out the units that appear at the top and the bottom of the fraction. x Slide 9: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 4: Multiply the numbers on the top and divide by what is on the bottom. x = Slide 10: Mole-mole calculations N2 + 3 H2 2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced? Slide 11: Mole-mole calculations N2 + 3 H2 2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced? x = Slide 12: Mole-mole calculations N2 + 3 H2 2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required? Slide 13: Mole-mole calculations N2 + 3 H2 2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required? x = You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
Mole to Mole Stoichiometry grazianir Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 685 Category: Entertainment License: All Rights Reserved Like it (1) Dislike it (0) Added: October 23, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: Stoichiometry The study of amounts in a chemical reaction Root words: Stoicheion – element Metron - measure Slide 2: Stoichiometry Steps Balance Chemical Equation Determine mole ratios Pick the correct mole ratio and multiply it by the moles of substance given. Mole Ratio : Mole Ratio A mole ratio is basically a fraction of the moles of one substance in a chemical reaction over the moles of another substance in the equation. Mole Ratios : Mole Ratios 2 H2(g) + O2(g) 2 H2O(l) Slide 5: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Slide 6: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 1: Write the number and unit given. Slide 7: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 2: Multiply by correct mole ratio to cancel out mole N2 and to get mole NH3 on top. x = Slide 8: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 3: Cancel out the units that appear at the top and the bottom of the fraction. x Slide 9: Mole-mole calculations N2 + 3 H2 2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 4: Multiply the numbers on the top and divide by what is on the bottom. x = Slide 10: Mole-mole calculations N2 + 3 H2 2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced? Slide 11: Mole-mole calculations N2 + 3 H2 2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced? x = Slide 12: Mole-mole calculations N2 + 3 H2 2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required? Slide 13: Mole-mole calculations N2 + 3 H2 2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required? x =