Mole to Mole Stoichiometry

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Slide 1:Stoichiometry The study of amounts in a chemical reaction Root words: Stoicheion – element Metron - measure


Slide 2:Stoichiometry Steps Balance Chemical Equation Determine mole ratios Pick the correct mole ratio and multiply it by the moles of substance given.


Mole Ratio :Mole Ratio A mole ratio is basically a fraction of the moles of one substance in a chemical reaction over the moles of another substance in the equation.


Mole Ratios :Mole Ratios 2 H2(g) + O2(g)  2 H2O(l)


Slide 5:Mole-mole calculations N2 + 3 H2  2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced?


Slide 6:Mole-mole calculations N2 + 3 H2  2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 1: Write the number and unit given.


Slide 7:Mole-mole calculations N2 + 3 H2  2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 2: Multiply by correct mole ratio to cancel out mole N2 and to get mole NH3 on top. x =


Slide 8:Mole-mole calculations N2 + 3 H2  2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 3: Cancel out the units that appear at the top and the bottom of the fraction. x


Slide 9:Mole-mole calculations N2 + 3 H2  2 NH3 If we have 2.00 mol of N2 reacting with sufficient H2, how many moles of NH3 will be produced? Step 4: Multiply the numbers on the top and divide by what is on the bottom. x =


Slide 10:Mole-mole calculations N2 + 3 H2  2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced?


Slide 11:Mole-mole calculations N2 + 3 H2  2 NH3 Suppose 6.00 mol of H2 reacted with sufficient nitrogen. How many moles of ammonia would be produced? x =


Slide 12:Mole-mole calculations N2 + 3 H2  2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required?


Slide 13:Mole-mole calculations N2 + 3 H2  2 NH3 We want to produce 2.75 mol of NH3. How many moles of nitrogen would be required? x =