Graph linear functions EXAMPLE 1 Graph the equation. Compare the graph with the graph of y = x . a . y = 2 x b . y = x + 3 SOLUTION a . The graphs of y = 2 x and y = x both have a y - intercept of 0 , but the graph of y = 2 x has a slope of 2 instead of 1.

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Graph linear functions EXAMPLE 1 b . The graphs of y = x + 3 and y = x both have a slope of 1, but the graph of y = x + 3 has a y - intercept of 3 instead of 0.

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Graph an equation in slope-intercept form EXAMPLE 2 Graph y = – x – 1 . 2 3 SOLUTION The equation is already in slope-intercept form. STEP 1 Identify the y -intercept. The y- intercept is – 1, so plot the point (0, – 1) where the line crosses the y- axis. STEP 2

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Graph an equation in slope-intercept form EXAMPLE 2 STEP 3 Identify the slope. The slope is – , or , so plot a second point on the line by starting at (0, – 1) and then moving down 2 units and right 3 units. The second point is (3, – 3). – 2 3 2 3

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Graph an equation in slope-intercept form EXAMPLE 2 Draw a line through the two points. STEP 4

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