logging in or signing up 08-06 SC aSGuest83417 Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 64 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: January 26, 2011 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: A B C D Factor x2 – 121. Factor –36x2 + 1. Solve 4c2 = 49 by factoring. Solve 25x3 – 9x = 0 by factoring. A square with sides from length b is removed from a square with sides of length 8. Write an expression to compare the area of the remaining figure to the area of the original square. Factors of 8m3 – 288m? Slide 2: Homework: Start Page 509 WM – 6 problems 13 – 59 odd CW – 8 problems 61 – 64 all HW – 37 problems 65 – 85 odd Slide 3: Then/Now New Vocabulary Key Concept: Factoring Perfect Square Trinomials Concept Summary: Factoring Methods Key Concept: Square Root Property Slide 4: You found the product of a sum and difference. (Lesson 7–8) Factor perfect square trinomials. Solve equations involving perfect squares. Slide 5: perfect square trinomial Slide 7: Recognize and Factor Perfect Square Trinomials A. Determine whether 25x2 – 30x + 9 is a perfect square trinomial. If so, factor it. 1. Is the first term a perfect square? Yes, 25x2 = (5x)2. 2. Is the last term a perfect square? Yes, 9 = 32. 3. Is the middle term equal to 2(5x)(3)? Yes, 30x = 2(5x)(3). Answer: 25x2 – 30x + 9 is a perfect square trinomial. 25x2 – 30x + 9 = (5x)2 – 2(5x)(3) + 32 Write as a2 – 2ab + b2. = (5x – 3)2 Factor using the pattern. Slide 8: Recognize and Factor Perfect Square Trinomials B. Determine whether 49y2 + 42y + 36 is a perfect square trinomial. If so, factor it. 1. Is the first term a perfect square? Yes, 49y2 = (7y)2. 2. Is the last term a perfect square? Yes, 36 = 62. 3. Is the middle term equal to 2(7y)(6)? No, 42y ≠ 2(7y)(6). Answer: 49y2 + 42y + 36 is not a perfect square trinomial. Slide 10: Factor Completely A. Factor 6x2 – 96. First check for a GCF. Then, since the polynomial has two terms, check for the difference of squares. = 6(x + 2)(x – 2) Factor the difference of squares. 6x2 – 96 = 6(x2 – 16) 6 is the GCF. = 6(x2 – 42) x2 = x ● x and 16 = 4 ● 4 Answer: 6(x + 2)(x – 2) Slide 11: Factor Completely B. Factor 16y2 + 8y – 15. This polynomial has three terms that have a GCF of 1. While the first term is a perfect square, 16y2 = (4y)2, the last term is not. Therefore, this is not a perfect square trinomial. This trinomial is in the form ax2 + bx + c. Are there two numbers m and p whose product is 16 ● –15 or –240 and whose sum is 8? Yes, the product of 20 and –12 is –240 and their sum is 8. Slide 12: Factor Completely 16y2 + 8y – 15 = 16y2 + mx + px – 15 Write the pattern. = 16y2 + 20y – 12y – 15 m = 20 and p = –12 = (16y2 + 20y) + (–12y – 15) Group terms with common factors. = 4y(4y + 5) – 3(4y + 5) Factor out the GCF from each grouping. Slide 13: Factor Completely = (4y + 5)(4y – 3) 4y + 5 is the common factor. Answer: (4y + 5)(4y – 3) Slide 14: Solve Equations with Repeated Factors Solve 4x2 + 36x = –81. 4x2 + 36x = –81 Original equation 4x2 + 36x + 81 = 0 Add 81 to each side. (2x)2 + 2(2x)(9) + 92 = 0 Recognize 4x2 + 36x + 81 as a perfect square trinomial. (2x + 9)2 = 0 Factor the perfect square trinomial. (2x + 9)(2x + 9) = 0 Write (2x + 9)2 as two factors. Slide 15: Solve Equations with Repeated Factors 2x + 9 = 0 Set the repeated factor equal to zero. 2x = –9 Subtract 9 from each side. Divide each side by 2. Slide 17: Use the Square Root Property A. Solve (b – 7)2 = 36. (b – 7)2 = 36 Original equation Answer: The roots are 1 and 13. Check each solution in the original equation. Square Root Property b = 7 + 6 or b = 7 – 6 Separate into two equations. = 13 = 1 Simplify. Slide 18: Use the Square Root Property B. Solve (x + 9)2 = 8. (x + 9)2 = 8 Original equation Square Root Property Slide 19: Solve an Equation PHYSICAL SCIENCE A book falls from a shelf that is 60 inches above the floor. A model for the height h in feet of an object dropped from an initial height of h0 feet is h = –16t2 + h0 , where t is the time in seconds after the object is dropped. Use this model to determine approximately how long it took for the book to reach the ground. h = –16t2 + h0 Original equation 0 = –16t2 + 5 Replace h with 0 and h0 with 5. –5 = –16t2 Subtract 5 from each side. 0.3125 = t2 Divide each side by –16. Slide 20: Solve an Equation Answer: Since a negative number does not make sense in this situation, the solution is 0.56. This means that it takes about 0.56 second for the book to reach the ground. ±0.56 ≈ t Take the square root of each side. Slide 21: YOU DO IT!!! Slide 22: A B C D A. Determine whether 9x2 – 12x + 16 is a perfect square trinomial. If so, factor it. Slide 23: A B C D B. Determine whether 49x2 + 28x + 4 is a perfect square trinomial. If so, factor it. Slide 24: A B C D A. Factor the polynomial 3x2 – 3. Slide 25: A B C D B. Factor the polynomial 4x2 + 10x + 6. Slide 26: A B C D Solve 9x2 – 30x + 25 = 0. Slide 27: A B C D A. Solve the equation (x – 4)2 = 25. Check your solution. Slide 28: A B C D B. Solve the equation (x – 5)2 = 15. Check your solution. Slide 29: A B C D PHYSICAL SCIENCE An egg falls from a window that is 10 feet above the ground. A model for the height h in feet of an object dropped from an initial height of hO feet is h = –16t2 + hO, where t is the time in seconds after the object is dropped. Use this model to determine approximately how long it took for the egg to reach the ground. Slide 30: Homework: Start Page 509 WM – 6 problems 13 – 59 odd CW – 8 problems 61 – 64 all HW – 37 problems 65 – 85 odd You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
08-06 SC aSGuest83417 Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 64 Category: Education License: All Rights Reserved Like it (0) Dislike it (0) Added: January 26, 2011 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide 1: A B C D Factor x2 – 121. Factor –36x2 + 1. Solve 4c2 = 49 by factoring. Solve 25x3 – 9x = 0 by factoring. A square with sides from length b is removed from a square with sides of length 8. Write an expression to compare the area of the remaining figure to the area of the original square. Factors of 8m3 – 288m? Slide 2: Homework: Start Page 509 WM – 6 problems 13 – 59 odd CW – 8 problems 61 – 64 all HW – 37 problems 65 – 85 odd Slide 3: Then/Now New Vocabulary Key Concept: Factoring Perfect Square Trinomials Concept Summary: Factoring Methods Key Concept: Square Root Property Slide 4: You found the product of a sum and difference. (Lesson 7–8) Factor perfect square trinomials. Solve equations involving perfect squares. Slide 5: perfect square trinomial Slide 7: Recognize and Factor Perfect Square Trinomials A. Determine whether 25x2 – 30x + 9 is a perfect square trinomial. If so, factor it. 1. Is the first term a perfect square? Yes, 25x2 = (5x)2. 2. Is the last term a perfect square? Yes, 9 = 32. 3. Is the middle term equal to 2(5x)(3)? Yes, 30x = 2(5x)(3). Answer: 25x2 – 30x + 9 is a perfect square trinomial. 25x2 – 30x + 9 = (5x)2 – 2(5x)(3) + 32 Write as a2 – 2ab + b2. = (5x – 3)2 Factor using the pattern. Slide 8: Recognize and Factor Perfect Square Trinomials B. Determine whether 49y2 + 42y + 36 is a perfect square trinomial. If so, factor it. 1. Is the first term a perfect square? Yes, 49y2 = (7y)2. 2. Is the last term a perfect square? Yes, 36 = 62. 3. Is the middle term equal to 2(7y)(6)? No, 42y ≠ 2(7y)(6). Answer: 49y2 + 42y + 36 is not a perfect square trinomial. Slide 10: Factor Completely A. Factor 6x2 – 96. First check for a GCF. Then, since the polynomial has two terms, check for the difference of squares. = 6(x + 2)(x – 2) Factor the difference of squares. 6x2 – 96 = 6(x2 – 16) 6 is the GCF. = 6(x2 – 42) x2 = x ● x and 16 = 4 ● 4 Answer: 6(x + 2)(x – 2) Slide 11: Factor Completely B. Factor 16y2 + 8y – 15. This polynomial has three terms that have a GCF of 1. While the first term is a perfect square, 16y2 = (4y)2, the last term is not. Therefore, this is not a perfect square trinomial. This trinomial is in the form ax2 + bx + c. Are there two numbers m and p whose product is 16 ● –15 or –240 and whose sum is 8? Yes, the product of 20 and –12 is –240 and their sum is 8. Slide 12: Factor Completely 16y2 + 8y – 15 = 16y2 + mx + px – 15 Write the pattern. = 16y2 + 20y – 12y – 15 m = 20 and p = –12 = (16y2 + 20y) + (–12y – 15) Group terms with common factors. = 4y(4y + 5) – 3(4y + 5) Factor out the GCF from each grouping. Slide 13: Factor Completely = (4y + 5)(4y – 3) 4y + 5 is the common factor. Answer: (4y + 5)(4y – 3) Slide 14: Solve Equations with Repeated Factors Solve 4x2 + 36x = –81. 4x2 + 36x = –81 Original equation 4x2 + 36x + 81 = 0 Add 81 to each side. (2x)2 + 2(2x)(9) + 92 = 0 Recognize 4x2 + 36x + 81 as a perfect square trinomial. (2x + 9)2 = 0 Factor the perfect square trinomial. (2x + 9)(2x + 9) = 0 Write (2x + 9)2 as two factors. Slide 15: Solve Equations with Repeated Factors 2x + 9 = 0 Set the repeated factor equal to zero. 2x = –9 Subtract 9 from each side. Divide each side by 2. Slide 17: Use the Square Root Property A. Solve (b – 7)2 = 36. (b – 7)2 = 36 Original equation Answer: The roots are 1 and 13. Check each solution in the original equation. Square Root Property b = 7 + 6 or b = 7 – 6 Separate into two equations. = 13 = 1 Simplify. Slide 18: Use the Square Root Property B. Solve (x + 9)2 = 8. (x + 9)2 = 8 Original equation Square Root Property Slide 19: Solve an Equation PHYSICAL SCIENCE A book falls from a shelf that is 60 inches above the floor. A model for the height h in feet of an object dropped from an initial height of h0 feet is h = –16t2 + h0 , where t is the time in seconds after the object is dropped. Use this model to determine approximately how long it took for the book to reach the ground. h = –16t2 + h0 Original equation 0 = –16t2 + 5 Replace h with 0 and h0 with 5. –5 = –16t2 Subtract 5 from each side. 0.3125 = t2 Divide each side by –16. Slide 20: Solve an Equation Answer: Since a negative number does not make sense in this situation, the solution is 0.56. This means that it takes about 0.56 second for the book to reach the ground. ±0.56 ≈ t Take the square root of each side. Slide 21: YOU DO IT!!! Slide 22: A B C D A. Determine whether 9x2 – 12x + 16 is a perfect square trinomial. If so, factor it. Slide 23: A B C D B. Determine whether 49x2 + 28x + 4 is a perfect square trinomial. If so, factor it. Slide 24: A B C D A. Factor the polynomial 3x2 – 3. Slide 25: A B C D B. Factor the polynomial 4x2 + 10x + 6. Slide 26: A B C D Solve 9x2 – 30x + 25 = 0. Slide 27: A B C D A. Solve the equation (x – 4)2 = 25. Check your solution. Slide 28: A B C D B. Solve the equation (x – 5)2 = 15. Check your solution. Slide 29: A B C D PHYSICAL SCIENCE An egg falls from a window that is 10 feet above the ground. A model for the height h in feet of an object dropped from an initial height of hO feet is h = –16t2 + hO, where t is the time in seconds after the object is dropped. Use this model to determine approximately how long it took for the egg to reach the ground. Slide 30: Homework: Start Page 509 WM – 6 problems 13 – 59 odd CW – 8 problems 61 – 64 all HW – 37 problems 65 – 85 odd