logging in or signing up method of joint meerule Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 4942 Category: Education License: All Rights Reserved Like it (8) Dislike it (0) Added: April 01, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... By: bijupmd (14 month(s) ago) Nice work, i would like to download it. Any hope? Saving..... Post Reply Close Saving..... Edit Comment Close By: kirivong (16 month(s) ago) Very good presentation, can I download it. Thanks Saving..... Post Reply Close Saving..... Edit Comment Close Premium member Presentation Transcript 3-3 The Method of Joints : 1 3-3 The Method of Joints Satisfying the equilibrium eqns for the forces exerted on the pin at each joint of the truss When using this method, it is necessary to draw each joint’s free body diagram before applying the eqns Consider joint B of the truss in Fig 3.19(a) From the free-body diagram in Fig 3.19(b), the unknowns are the magnitude of forces in members BA & BC Applications of eqns yields 2 algebraic eqns that can be solved for the 2 unknowns 3-3 The Method of Joints : 2 3-3 The Method of Joints Fig 3.19 3-3 The Method of Joints : 3 3-3 The Method of Joints Always assume the unknown member forces acting on the joint’s free body diagram to be in tension Numerical solution of the equilibrium eqns will yield positive scalars for members in tension & negative for those in compression The correct sense of direction of an unknown member force can in many cases be determined by inspection 3-3 The Method of Joints : 4 3-3 The Method of Joints A +ve answer indicates that the sense is correct, whereas a –ve answer indicates that the sense shown on the free-body diagram must be reversed Example 3.2 : 5 Example 3.2 Determine the force in each member of the roof truss shown in Fig 3.20(a) State whether the members are in tension or compression The reactions at the supports are given Fig 3.20(a) Example 3.2 - solution : 6 Example 3.2 - solution Only the forces in half the members have to be determined as the truss is symmetric wrt both loading & geometry Example 3.2 - solution : 7 Example 3.2 - solution Example 3.2 - solution : 8 Example 3.2 - solution 3-4 Zero-Force Members : 9 3-4 Zero-Force Members Truss analysis using method of joints is greatly simplified if one is able to first determine those members that support no loading These zero-force members may be necessary for the stability of the truss during construction & to provide support if the applied loading is changed The zero-force members of a truss can generally be determined by inspection of the joints & they occur in 2 cases. 3-4 Zero-Force Members : 10 3-4 Zero-Force Members Case 1 Consider the truss in Fig 3.22(a) The 2 members at joint C are connected together at a right angle & there is no external load on the joint The free-body diagram of joint C indicates that the force in each member must be zero in order to maintain equilibrium 3-4 Zero-Force Members : 11 3-4 Zero-Force Members Case 2 Zero-force members also occur at joints having a geometry as joint D in Fig 3.23(a) 3-4 Zero-Force Members : 12 3-4 Zero-Force Members Case 2 No external load acts on the joint, so a force summation in the y-direction which is perpendicular to the 2 collinear members requires that FDF = 0 Using this result, FC is also a zero-force member, as indicated by the force analysis of joint F, Fig 3.23(c) Example 3.4 : 13 Example 3.4 Using the method of joints, indicate all the members of the truss shown in Fig 3.24(a) that have zero force Fig 3.24(a) Example 3.4 - solution : 14 Example 3.4 - solution Looking for joints similar to those discussed in Fig 3.22 and 3.23, we have: Example 3.4 - solution : 15 Example 3.4 - solution You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
method of joint meerule Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINT lite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 4942 Category: Education License: All Rights Reserved Like it (8) Dislike it (0) Added: April 01, 2009 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... By: bijupmd (14 month(s) ago) Nice work, i would like to download it. Any hope? Saving..... Post Reply Close Saving..... Edit Comment Close By: kirivong (16 month(s) ago) Very good presentation, can I download it. Thanks Saving..... Post Reply Close Saving..... Edit Comment Close Premium member Presentation Transcript 3-3 The Method of Joints : 1 3-3 The Method of Joints Satisfying the equilibrium eqns for the forces exerted on the pin at each joint of the truss When using this method, it is necessary to draw each joint’s free body diagram before applying the eqns Consider joint B of the truss in Fig 3.19(a) From the free-body diagram in Fig 3.19(b), the unknowns are the magnitude of forces in members BA & BC Applications of eqns yields 2 algebraic eqns that can be solved for the 2 unknowns 3-3 The Method of Joints : 2 3-3 The Method of Joints Fig 3.19 3-3 The Method of Joints : 3 3-3 The Method of Joints Always assume the unknown member forces acting on the joint’s free body diagram to be in tension Numerical solution of the equilibrium eqns will yield positive scalars for members in tension & negative for those in compression The correct sense of direction of an unknown member force can in many cases be determined by inspection 3-3 The Method of Joints : 4 3-3 The Method of Joints A +ve answer indicates that the sense is correct, whereas a –ve answer indicates that the sense shown on the free-body diagram must be reversed Example 3.2 : 5 Example 3.2 Determine the force in each member of the roof truss shown in Fig 3.20(a) State whether the members are in tension or compression The reactions at the supports are given Fig 3.20(a) Example 3.2 - solution : 6 Example 3.2 - solution Only the forces in half the members have to be determined as the truss is symmetric wrt both loading & geometry Example 3.2 - solution : 7 Example 3.2 - solution Example 3.2 - solution : 8 Example 3.2 - solution 3-4 Zero-Force Members : 9 3-4 Zero-Force Members Truss analysis using method of joints is greatly simplified if one is able to first determine those members that support no loading These zero-force members may be necessary for the stability of the truss during construction & to provide support if the applied loading is changed The zero-force members of a truss can generally be determined by inspection of the joints & they occur in 2 cases. 3-4 Zero-Force Members : 10 3-4 Zero-Force Members Case 1 Consider the truss in Fig 3.22(a) The 2 members at joint C are connected together at a right angle & there is no external load on the joint The free-body diagram of joint C indicates that the force in each member must be zero in order to maintain equilibrium 3-4 Zero-Force Members : 11 3-4 Zero-Force Members Case 2 Zero-force members also occur at joints having a geometry as joint D in Fig 3.23(a) 3-4 Zero-Force Members : 12 3-4 Zero-Force Members Case 2 No external load acts on the joint, so a force summation in the y-direction which is perpendicular to the 2 collinear members requires that FDF = 0 Using this result, FC is also a zero-force member, as indicated by the force analysis of joint F, Fig 3.23(c) Example 3.4 : 13 Example 3.4 Using the method of joints, indicate all the members of the truss shown in Fig 3.24(a) that have zero force Fig 3.24(a) Example 3.4 - solution : 14 Example 3.4 - solution Looking for joints similar to those discussed in Fig 3.22 and 3.23, we have: Example 3.4 - solution : 15 Example 3.4 - solution