QUESTION 2:- Show that: (i) tan 48o tan 23o tan 42o tan67o = 1 (ii) cos38o cos52o – sin38o sin52o = 0:
QUESTION 2:- Show that: (i) tan 48o tan 23o tan 42o tan67o = 1 (ii) cos38o cos52o – sin38o sin52o = 0
QUESTION 3 :-If tan 2A = cot (A – 18o), where 2A is an acute angle, find the value of A.:
QUESTION 3 :- If tan 2A = cot (A – 18o), where 2A is an acute angle, find the value of A.
QUESTION 4:-If tan A = cot B, prove that A + B = 90o.:
QUESTION 4:- If tan A = cot B, prove that A + B = 90o.
Let ‘s meet again