5-1b Bisectors

Views:
 
Category: Education
     
 

Presentation Description

No description available.

Comments

Presentation Transcript

Sec. 5-1b Bisectors in Δs:

Sec. 5-1b Bisectors in Δ s Objectives: 1) To use properties of  bisectors and  bisectors.

Perpendicular Bisector Theorem:

CD is the  bisector of Δ ABC CD is the bisector or AB CD is the  bisector of ACB Perpendicular Bisector Theorem If a point is on the  bisector of a segment, then it is equidistant from the endpoints of the segments. C A D B Δ ADC  Δ BDC by SAS Any point on CD is the same distance from Pt. A and from Pt. B

Converse of the Perpendicular Bisector Theorem:

Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the  bisector of the segments. Locus Theorems – A set of points that satisfy a given condition.

Slide 4:

** Distance from a point to a line is the length of the perpendicular segment from the point to the line. P A D B The distance from P to AB is the length of PD.

Th(5 – 4)  Bisector Thm.:

Th(5 – 4)  Bisector Thm. If a point is on the bisector of an , then the point is equidistant from the sides of the . A B C D ABD  CBD The distance from D to AB is AD The distance from D to BC is DC Δ ABD  Δ CBD by AAS AB  CB and AD  CD 1 2 1  2

Slide 6:

A B C

Example 2::

Example 2: B C D F 2x + 24 5x Find FD 5x = 2x + 24 3x = 24 x = 8 FD = 2x + 24 = 2(8) +24 = 16 + 24 = 40

Slide 8:

B C D F Example 3: 2x (x + 20) Find m BCD 2x = x + 20 x = 20 m  BCF = 2x = 2(20) = 40 m  BCD = 2m  BCF = 2(40) = 80 40 40 80

Slide 9:

Page 267 1-48 Skip any 4