eiko 060920 ilc

Response and Resolution of Cerenkov Dual-Readout Calorimeter (Simulation Only): 

Response and Resolution of Cerenkov Dual-Readout Calorimeter (Simulation Only) Shin-Shan Yu, Adam Para, Hans Wenzel Fermi National Accelerator Laboratory September 20th, 2006

Why?: 

Why? Goal Improve resolution of the measured hadronic energy (sE/E)× sqrt(E) a constant and small (30%) Normalized response ~ 1 Dual-readout use information both from Cerenkov and ionization signals to obtain the Em fraction (fem) in the jet for each event 20 GeV p- 20 GeV p- Normalized pion response : ioniziation Normalized pion response : Cerenkov From lead glass

Response of A Pion in the Detector: 

Response of A Pion in the Detector Solve fem? Or use “x” to represent fem?

X vs. fem: 

X vs. fem x and fem have a one-to-one relation We use x to find out the correction formula for pion of each energy If x=1, fem=1

How? Part I: 

How? Part I dualRCalor package Generate 5000 events with a single pion or electron shooting at the calorimeter (fixed incident point) Study response and resolution One big block of lead glass, 100 m depth 1500 layers of 20 mm lead glass, 5 mm scintillator Kinetic energy of pion: 1, 5, 10, 20 and 50 GeV Study sampling fraction Fix active layer depth (5 mm) and pion kinetic energy at 20 GeV Use lead glass in the active layer Cerenkov layer depth: 10, 20, 50, 75 mm Use scintillator in the active layer

How? Part II: 

How? Part II Store information Total ionization energy deposited in the Cerenkov and active layers (Eion) Total energy of Cerenkov photons (Epho) Total energy of the incident particle (kinetic energy + mass) (Egun) X= Epho/Eion Normalize pion response to that of electron check Eion vs. Epho of electron Derive correction formula Fit Eion / Egun as a function of (1- Epho/Eion X slope) Make the correction Divide Eion / Egun by (1- Epho/Eion X slope) of ionization of ionization

Deriving the Correction Formula: 

Deriving the Correction Formula 20 GeV pion, Cerenkov layer depth: 20 mm Active layer depth: 5 mm (lead glass) Eion/Egun 1-slope×Epho/Eion

One Big Block of Lead Glass (100 m): 

One Big Block of Lead Glass (100 m) 25%

1500 Layers of 20 mm Lead Glass and 5 mm Scintillator: 

1500 Layers of 20 mm Lead Glass and 5 mm Scintillator 35%

The Scintillator Is Different from the Lead Glass: 

The Scintillator Is Different from the Lead Glass The hydrogen in scintillator traps neutron Now scintillator acts like a compensating material In order to separate the sampling fraction effect from the compensation, try using lead glass as the active material 20 GeV p- 20 GeV p- 20 GeV pion, Cerenkov layer depth: 20 mm, Active layer depth: 5 mm From scintillator

Active Layer: Lead Glass: 

Active Layer: Lead Glass

Active Layer: Scintillator: 

Active Layer: Scintillator

Conclusion & To-do: 

Conclusion & To-do For Cerenkov layer depth < 50 mm, the resolution of the scintillator active layer is better than that of the lead glass active layer But why is the improvement still not significant? Any suggestions? Ideas? Fix the Cerenkov layer depth and vary the active layer depth