Dear Sir,
This presentation is just great. Is it possible to allow me to have the presentation so that i can teach my students. my e-mail address is
amarifam2@yahoo.com

hey the ppt is too good if you cud just help me bye sending the ppt to my id : mihir_kanani777@yahoo.com
and even helping me out wid the other subtracting and division methods.. it would b of great he;p.. thanking you in anticipation..

Vedic Mathematics Session Topics
Multiplication with common base
Squares
Cubes
Two digit multiplication
Three digit multiplication
By Munish Kumar

Slide2:

Multiplication with common base # Multiply 104 by 103 1 0 4
1 0 3 x 3 1 2 1 0 4 x x 0 0 0 x 1 0 7 1 2 Magic of Vedic 1 0 4
1 0 3 Here Common base is 100 4
3 1 2 1 0 7 (1 0 4 + 3 ) or (1 0 3 + 4) 4 x 3

Slide3:

Some problems to practice 105 x 107 102 x 108 107 x 109 102 x 103 104 x 112

Slide4:

Let us do some more multiplications 1 0 0 1
1 0 1 9 01
19 1 9 1 0 2 0 (1001 + 19 ) or (1 019 + 01) 01 x 19 Since the base is 1000, we take 3 digits on the right side 1,0 2 0,0 1 9 x 0 1 9

Slide5:

Some practice problems 1005 x 1007 1002 x 1008 1004 x 1012 1013 x 1003

Slide6:

Multiplication with less than base 9 7
8 9 - 3
- 11 3 3 8 6 (9 7 - 11 ) or (89 - 03) -11 x -3 8 6 3 3 x

Slide7:

Let us do some practice 95 x 97 92 x 98 97 x 89 92 x 93

Slide8:

Squares Squares from 101 to 125 (101)2
(109)2
(112)2
(117)2
(123)2

Slide9:

Squares from 75 to 99 Squares (97)2
(93)2
(89)2
(85)2
(77)2

Slide10:

Squares of numbers ending with 5 Squares Formula used (a5)2 = a(a+1) Ι 25 Where, a = Digits in the number other than 5 (25)2
(45)2
(95)2
(995)2
(1035)2 (25)2 =2(2+1) Ι 25 = 6 2 5 Here a = 2 (95)2 = 9(9+1) Ι 25 = 9025 Here a= 9 (45)2 = 4(4+1) Ι 25 = 2 0 2 5 Here a= 4 (995)2 = 99(99 + 1) Ι 25 = 990025 Here a = 99 (1035)2 = 103(103 + 1) Ι 25 = 1071225 Here a = 103

Slide11:

Squares Squares from 25 to 49 (47)2
(43)2
(39)2
(35)2
(27)2 Formula used N2 = ( 25 – X ) Ι X2 Where, X = By how much a number less than 50 (47)2 = (25 – 3) Ι 32 = 2 2 0 9 Here X = 3 (39)2 = (25 – 11) Ι 112 = 14 Ι 121 = 1 5 2 1 Here X = 11 (43)2 = (25 – 7) Ι 72 = 1 8 4 9 Here X = 7 (35)2 = (25 – 15) Ι 152 = 10 Ι 225 = 1 2 2 5 Here X = 15 (27)2 = (25 – 23) Ι 232 = 02 Ι 529 = 7 2 9 Here X = 23

Slide12:

Squares Squares from 51 to 74 (52)2
(58)2
(63)2
(65)2
(72)2 Formula used N2 = ( 25 + X ) Ι X2 Where, X = By how much a number is more than 50 (52)2 = (25 + 2) Ι 22 = 2 7 0 4 Here X = 2 (63)2 = (25 + 13) Ι 132 = 3 8 Ι 169 = 3 9 6 9 Here X = 13 (58)2 = (25 + 8) Ι 82 = 3 3 6 4 Here X = 8 (65)2 = (25 + 15) Ι 152 = 40 Ι 225 = 4 2 2 5 Here X = 15 (72)2 = (25 + 22) Ι 222 = 47 Ι 484 = 5 1 8 4 Here X = 22

Slide13:

Ending with 5 and difference 10 25 x 35 =
45 x 55 =
115 x 125 =
195 x 205 =
505 x 495 = 8 7 5 ALWAYS (32 – 1) = 8 2,475 14,375 39,975 2,49,975 What is the similarity in the following

Slide14:

Base same and unit digits sum 10 53 x 57 =
26 x 24 =
117 x 113 =
109 x 101 =
55 x 55 = 30 21 7 x 3 5 x 6 624 13,221 11,009 3,025 What is the similarity in the following

Slide15:

Cubes Formula used (N)3 = b + 3x Ι 3x2 Ι x3 Where, x = Difference from the base & b = base (104)3
(12)3
(95)3
(995)3
(1007)3 (104)3 = (100 + 3 x 4) Ι 3 x 42 Ι 43 = (100 +12) Ι 3 x 16 Ι 64 = 1 1 2 4 8 6 4 Here b = 100 & x = 4 (12)3 = (10 + 3 x 2) Ι 3 x 22 Ι 23 = (10 +6 ) Ι 3 x 4 Ι 8 = 16 Ι 12 Ι 8 = 1 7 2 8 Here b = 10 & x = 2 (95)3 = (100 + 3 x -5) Ι 3 x (-5)2 Ι (-5)3 = (100 -15) Ι 75 Ι -125 = 85 Ι 73 Ι 200 -125 = 8 5 7 3 7 5 Here, b = 100 & x = -5 Since the base is 10 . We will take only on digit in each block and carry forward the extra to consecutive next block in the left. Since we have a negative term in the extreme right block. So have to make it positive by borrowing 2 carry from consecutive left block and add to -125. (995)3 = (1000 + 3 x -5) Ι 3 x (-5)2 Ι (-5)3 = (1000 -15) Ι 75 Ι -125 = 985 Ι 073 Ι 200 -125 = 9 8 5, 0 7 3, 0 7 5 Here, b = 1000 & x = -5 As the base here is 1000, so we will take three digits in each block after making negative term in the extreme right block positive (1007)3 = (1000 + 3 x 7) Ι 3 x (7)2 Ι (7)3 = (1000 +21) Ι 147 Ι 343 = 1021 Ι 147 Ι 343 = 1 0, 2 1 1, 4 7, 3 4 3 Here, b = 1000 & x = 7

Slide16:

Three step multiplication # Multiply 36 by 94 3 6
9 4 x 6 x 4 = 24 3 x 4 + 9 x 6 = 66 9 x 3 = 27 2 7 6 6 2 4

Slide17:

Let us do some more multiplications 1 1 1
1 1 3 11
13 1 4 3 1 2 4 (1 1 1 + 13 ) or (1 1 3 + 11) 11 x 13 This 1 is carried forward to the other side 1 2 5 4 3 x

Slide18:

Multiplication in different mood 9 7
1 0 9 - 3
+ 9 -2 7 1 0 6 (9 7 + 9 ) or (109 - 03) 9 x -3 x Since we have a negative term on the right side of it So we will make it positive . For that we will borrow carry from left side, which is equal to 100 and add -27 to it 100 - 27 = 73 106 – 1 = 105 7 3 105 1 0,5 7 3

Slide19:

Thank you Best of luck for your future

You do not have the permission to view this presentation. In order to view it, please
contact the author of the presentation.

Send to Blogs and Networks

Processing ....

Premium member

Use HTTPs

HTTPS (Hypertext Transfer Protocol Secure) is a protocol used by Web servers to transfer and display Web content securely. Most web browsers block content or generate a “mixed content” warning when users access web pages via HTTPS that contain embedded content loaded via HTTP. To prevent users from facing this, Use HTTPS option.

By: adikulal (67 month(s) ago)

plz send this ppt to aditya.kulal@gmail.com!