Slide1 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Module #17B:
Acid Base Ionization
Computations
Slide2 : To determine if our protein unfolds or not is it sufficient to know the Ka and Kb
Values of the functional groups?
Slide3 : 3D structure of ALAD directs
Reactants into proper orientation 2 1 3D structure controlled by proper hydrogen and ionic bonds, pH dependent!!!!!!!
Slide4 : Zn2+ Control of protein shape is due to fraction of sites charged R refers to rest of protein Phosphoenolate carboxylase, human, cys cysteine http://www.biology.arizona.edu/biochemistry/problem_sets/aa/aa.html
Slide5 : Protein folding due to
FRACTION of sites charged Hemeglobin
Slide6 : % Ionized (dissociated) This seems pretty straight forward
Slide7 : Calculating [A-] This will require knowing [H3Oaq+] AND a new vocabulary for comparing the solution acidity from experiment to experiment Ka and Kb tell us about the possibility
Of donating protons, not what the solution
Acidity is Define another comparison number: pH
Slide8 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm pH, pOH, pKa Module #17B:
Acid Base Ionization
Computations
Slide9 : Chemists are _____
To shorten calculations use log LAZY
Slide10 : Assumption that 55.5 molar is relative unchanged
Slide11 : pH scale runs from 0 to 14 Which is more
Acidic?
Slide12 : acid/base ave [H+] pH pOH ave [OH-]
base blood 5.01x10-8
saliva 1x10-7
acid urine 2.51x10-7
cow’s milk 3.54x10-7
cheese 7.94x10-6
7.3 7 # is slightly larger than 10-8, so I know it is 7….. something 14-7.3=6.7 6.7 1.99x10-7 You do the rest
Slide13 : cysteine What are the two
pKas? What is the Ka of a compound
Whose pKa is 3.7?
Slide14 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Module #17B:
Acid Base Ionization
Computations
Slide15 : Calculating [A-] This will require an equilibrium calculation
Slide16 : Generalized Strategy involves comparing Kas Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
a. Strong electrolyte: HNO3, HCl, H2SO4 (No Clean Socks)
b. Give all strong acid protons to water or alpha dog
c. Calculate hydronium conc.
d. Calculate pH
2. Weak Acid
Identify strongest acid (omega dog, can not hold protons)
Has largest Ka; smallest charge density anion
Calculate how many protons omega gives up (equil)
Calculate pH
Use to determine what alpha gets
Slide17 : Example Calculations
HCl
Acetic acid (vinegar)
HF
B(OH)3 (Boric acid (eye wash))
Mixture (HF and phenol)
Mixture (H2SO4, HSO4-)
Triethylamine
NaAcetate
Our heme example Calculate the pH of 0.004 M HCl
Slide18 : Generalized Strategy involves comparing Kas Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
Strong electrolyte: HNO3, HCl, H2SO4 (No Clean Socks)
b. Give all strong acid protons to water or alpha present
c. Calculate hydronium conc.
d. Calculate pH Omega dog
Slide19 : Scientific notation allows you to quickly check if
Your answer is in the right “ballpark” pH has to be slightly less
Than 3
Slide20 : Example Calculations
HCl
Acetic acid (vinegar)
HF
B(OH)3 (Boric acid (eye wash))
Mixture (HF and phenol)
Mixture (H2SO4, HSO4-)
Triethylamine
NaAcetate
Our heme example
Slide21 : Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
a. Strong electrolyte: HNO3, HCl, H2SO4 (None)
2. Weak Acid:
Calculate how many protons omega gives up (equil) Example: What is the % ionization of commercial vinegar? The label reads 5% acidity (by weight). Vinegar is acetic acid which has the formula HC2H3O2. (CH3COOH) Ka = 1.8x10-5
Density of 5% acetic acid 1.0023 g/mL
Slide22 : Example: What is the % ionization of commercial vinegar? The label reads 5% acidity (by weight). Vinegar is acetic acid which has the formula HC2H3O2. (CH3COOH) Ka = 1.8x10-5
Density of 5% acetic acid 1.0023g/mL % by wt.
Ka = 1.8x10-5 Know Don’t Know Need the initial molarity need the final dissociation
Slide23 : HC2H3O2 C2H3O2- H+
stoic 1 1 1
conc. init 5% 0 10-7
[Init] 0.8355 0 10-7
Change -x +x +x
Assume 0.8355>>x +x 10-7 << x
[Equil] 0.8355 +x +x H2O OH- H+
55.5 10-7 10-7 Why complicate this situation by adding in 10-7
When we get rid off it with an assumption? Because it creates a habit necessary of multiple rx What is the % ionization of commercial vinegar? The label reads 5% acidity (by weight). Density of 5% acetic acid is 1.0023 g/mL. Vinegar is acetic acid which has the formula HC2H3O2. (CH3COOH) Ka = 1.8x10-5
Slide24 : Check: HA A H+
Assume 0.8355>>x +x 10-7 << x Sig figs + - Original sig figs
were = 0.83
So if we round to
2 sig fig, have
Same answer
Slide25 : What is the % ionization of commercial vinegar? The label reads 5% acidity (by weight). Density of 5% acetic acid is 1.0023 g/mL. Vinegar is acetic acid which has the formula HC2H3O2. (CH3COOH) Ka = 1.8x10-5
Slide26 : How does % dissociation or ionization
vary with concentration? [Acetic Acid] % ionization
1.00 M 0.42%
0.835M 0.46%
0.1 M 1.3% Observations? % ionization increases with the lower molarity. Why should this be so? What is the % ionization of commercial vinegar? The label reads 5% acidity (by weight). Density of 5% acetic acid is 1.0023 g/mL. Vinegar is acetic acid which has the formula HC2H3O2. (CH3COOH) Ka = 1.8x10-5
Slide27 : Dilute by 10 (make less concentrated): What does this tell us, if anything? We have too many reactants, need to shift to
the right, or dissociate some more. general rule of thumb: dilution gives
more dissociation.
Slide28 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide29 : Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
a. Strong electrolyte: HNO3, HCl, H2SO4 (No Clean Socks)
2. Weak Acid
Identify strongest acid (omega dog, can not hold protons)
Has largest Ka; smallest charge density anion
Calculate how many protons omega gives up (equil) Calculate the F- of a solution of 1.00 M HF.
Ka= 7.2x10-4 No Strong Acids (SA)
Slide30 : H2O H+ OH-
55.5 10-7 10-7
HF(aq) H+from HF F-
stoic. 1 1 1
Init 1.0 10-7 0
Change -x +x +x
Assum 1>>x 10-7 <
Slide31 : Calculate the pH of a solution of 1.00 M HF.
K1 = 7.2x10-4 Check assumptions HF(aq) H+from HF F-
Init 1.0 10-7 0
Change -x +x +x
Assum 1>>x 10-7 <
Slide32 : Calculate the F- of a solution of 1.00 M HF.
K1 = 7.2x10-4 HF(aq) H+from HF F-
Init 1.0 10-7 0
Change -x +x +x
Assum 1>>x 10-7 <
Slide33 : Write down ALL possible reactions involving a proton
Identify proton donors
strong acids: No Clean Socks?
2. Weak acids:
Example: Boric acid is commonly used in eyewash solutions to neutralize bases splashed in the eye. It acts as a monoprotic acid, but the dissociation reaction looks different. Calculate the pH of a 0.75 M solution of boric acid, and the concentration of B(OH)4-.
No SA B(OH)3 Students do
This on your own
Slide34 : H2O OH- H+
55.5 10-7 10-7
B(OH)3 + H2O B(OH)4- + H+
stoic 1 n.a. 1 1
[Init] 0.75 0 10-7
Change -x +x +x
Assume 0.75>>x x 10-7<
Slide35 : B(OH)3 + H2O B(OH)4- + H+
[Init] 0.75 0 10-7
Change -x +x +x
Assume 0.75>>x x 10-7<
Slide36 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide37 : Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
2. Weak Acid
Identify strongest acid (omega dog, can not hold protons)
Has largest Ka; smallest charge density anion
Calculate how many protons omega gives up (equil)
Calculate pH (Use to determine what alpha gets)
Mixtures of Acids Calculate the pH of a solution that contains 1.0 M HF and 1.0 M HOC6 H5. Calculate the conc. of -OC6 H5 at this concentration. NONE
Slide38 : H2O OH- H+
55.5 10-7 10-7
HF + H2O F- + H+
stoic 1 n.a. 1 1
[Init] 1.0 0 10-7
Change -x +x +x
Assume 1.0>>x x 10-7<
Slide39 : HF + H2O F- + H+
stoic 1 n.a. 1 1
[Init] 1.0 0 10-7
Change -x +x +x
Assume 1.0>>x x 10-7<
Slide40 : HF + H2O F- + H+
stoic 1 n.a. 1 1
[Init] 1.0 0 10-7
Change -x +x +x
Assume 1.0>>x x 10-7<
Slide41 : HF + H2O F- + H+
stoic 1 n.a. 1 1
[Init] 1.0 0 10-7
Change -x +x +x
Assume 1.0>>x x 10-7<>x x x<<2.7x10-2
Equil 1.0 x 2.7x10-2
Slide42 : C6H5OH+ H2O C6H5O- + H+
stoic 1 n.a. 1 1
[Init] 1.0 0 2.7x10-2
Change -x +x +x
Assume 1.0>>x x x<<2.7x10-2
Equil 1.0 x 2.7x10-2 Calculate the pH of a solution that contains 1.0 M
HF and 1.0 M HOC6 H5. Calculate the conc.
of -OC6 H5 at this concentration.
Slide43 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide44 : Write down ALL possible reactions involving a proton
Excluding water, identify all the proton donors as
Strong acid
Strong electrolyte: HNO3, HCl, H2SO4 (No Clean Socks)
b. Give all strong acid protons to water or alpha dog Example: calculate the pH of 0.0010 M sulfuric acid
Slide45 : Example: calculate the pH of 0.0010
M sulfuric acid; Ka2 = 1.2x10-2 Pure Water H2O OH- H+
55.5 10-7 10-7
Control/complete H2SO4 HSO4- H+
stoic. 1 1 1
[init] .0010 0 10-7
complete 0 0.0010 0.0010+10-7
0 0.0010 0.0010
stoic. HSO4- H+ SO42-
1 1 1
[Init] 0.0010 0. 0010 0
Change -x +x +x
Assume? 0.0010>x 0.0010>x +x
[Equil] 0.0010 0.0010 x 1 2 3 NO!
Slide46 : Example: calculate the pH of 0.0010
M sulfuric acid; Ka2 = 1.2x10-2 stoic. HSO4- H+ SO42-
1 1 1
[Init] 0.0010 0. 0010 0
Change -x +x +x
Assume? 0.001>x 0.001>x +x
[Equil] 0.001-x 0.001+x x Here is our first example in which we can not make assumptions
Slide47 : [SO42-]=x Solution gives a neg
Number which is not allowed [H+]=0.001
+0.000865
0.001865 pH=-log(0.001865)=2.73
Slide48 : Alternative Strategy to
going to “exact equil. Expression” ITERATIVE SOLUTIONS Why? – because the real body or real world
Is much too complex to always be able to
Find an exact equilibrium expression Successive Approximations
(iterations)
Slide49 : Calculate proton concentration of 0.100 M HNO2 using the iterative method (Ka=6.0x10-4) Pure Water H2O OH- H+
55.5 10-7 10-7
HNO2 NO2 H+
stoic. 1 1 1
[Init] 0.100 0 10-7
Change -x +x +x
Assume 0.100>>x x x>>10-7
[Equil] 0.100 x x
Calc 1 7.7x10-3
New Equil 0.100-7.7x10-3 x’’ x’’
Calc 2 7.44x10-3
New New Equil 0.100-7.44x10-3 x’’’ x’’’
Calc 3 7.45x10-3 1 2 3 4
Slide50 : Converging, plausible answer for iterative
method: 0.100 M HNO2, Ka=6.0x10-4
Slide51 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Weak Bases Module #17B:
Acid Base Ionization
Computations
Slide52 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide53 : Calculation with Weak Base Calc. the [OH], [H], and pH of 0.20 M solns
of triethylamine, Kb = 4.0x10-4 Calc. the [OH], [H], and pH of 0.20 M solns
of triethylamine, Kb = 4.0x10-4 H2O H+ OH-
55.5 10-7 10-7
B H2O BH+ OH-
stoic 1 1 1 1
[Init] 0.20 0 10-7
Change -x +x +x
Assum 0.20>>x x 10-7 < x
Equil 0.20 x x 1 2
Slide54 : Calc. the [OH], [H], and pH of 0.20 M solns
of triethylamine, Kb = 4.0x10-4 H2O H+ OH-
55.5 10-7 10-7
B H2O BH+ OH-
stoic 1 1 1 1
[Init] 0.20 0 10-7
Change -x +x +x
Assum 0.20>>x x 10-7 < x
Equil 0.20 x x 1 2 Rounds to 0.0089 Rounds to 0.20
Slide55 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Salts Module #17B:
Acid Base Ionization
Computations
Slide56 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide57 : If we place Na acetate in solution (to make a 0.1 M
solution) what are the main species present? What
will be the pH of the solution? Ka = 1.8x10-5 Write all reactions involving protons, hydroxides Determine who is omega and will donate Hmm, a slight problem – we don’t know Kb
Slide58 : If we place Na acetate in solution (to make a 0.1 M
solution) what are the main species present? What
will be the pH of the solution? Ka = 1.8x10-5
Slide59 : H2O H+ OH-
55.5 10-7 10-7
CH3COO- + H2O = CH3COOH + OH-
stoich 1 1 1
[Init] 0.1 0 10-7
Change -x +x 10-7 +x
Sum 0.1-x 0+x 10-7 +x
Assume x<<<0.1 x>>>10-7
[Equil] 0.1 x x 1 2 If we place Na acetate in solution (to make a 0.1 M
solution) what are the main species present? What
will be the pH of the solution? Ka = 1.8x10-5
Slide60 : CH3COO- + H2O = CH3COOH + OH-
stoich 1 1 1
[Init] 0.1 0 10-7
Change -x +x 10-7 +x
Sum 0.1-x 0+x 10-7 +x
Assume x<<<0.1 x>>>10-7
[Equil] 0.1 x x If we place Na acetate in solution (to make a 0.1 M
solution) what are the main species present? What
will be the pH of the solution? Ka = 1.8x10-5 yes No
Slide61 : CH3COO- + H2O = CH3COOH + OH-
stoich 1 1 1
[Init] 0.1 0 10-7
Change -x +x 10-7 +x
Sum 0.1-x 0+x 10-7 +x
Assume x<<<0.1 x>>>10-7
[Equil] 0.1 x x
Equil new 0.1-x x x+10-7 If we place Na acetate in solution (to make a 0.1 M
solution) what are the main species present? What
will be the pH of the solution? Ka = 1.8x10-5
Slide62 : Before we got 7.45x10-6
Slide63 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Biological Chemistry Module #17B:
Acid Base Ionization
Computations
Slide64 : Example Calculations
HCl
Acetic acid (vinegar)
3. HF
4.B(OH)3 (Boric acid (eye wash)) (students
Do this one yourself)
5.Mixture (HF and phenol)
6.Mixture (H2SO4, HSO4-)
7.Triethylamine
8.NaAcetate
9.Our heme example
Slide65 : Hemeglobin
Slide66 : Which pH (2, 7, 11) is most favorable for the formation of a hydrogen bond between Val and tyr in hemoglobin assuming that we define favorable as having the most possible H bonds. Mass balance
Slide67 : Which pH (2, 4.7, 7, 11) is most favorable for the formation of a hydrogen bond between Val and tyr in hemoglobin assuming that we define favorable has having the most possible H bonds Repeat procedure
With tyrosine
Slide68 : Which pH is best? Hint: Want Val ionized
Tyr not ionized
Slide69 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Module #17B:
Acid Base Ionization
Computations When should we
Be making assumptions?
Slide70 : If 1.0 mol NOCl is placed in a 2.0 L flask what are the equilibrium concentrations of NO and Cl2 given that at 35 oC the equilibrium constant, Kc, is 1.6x10-5 mol/L? Red herrings:
Clues? 35 oC is a red herring K is “small” compared to others (<<< 1) we have worked with !!!!! Example on Using Simplifications We will define
Small in the
Next chapter! Kc is 0.64. Example 2 EXAMPLE 3: Kc = 0.36M Example 4: Kp is 1x10-2. Module 17A
Slide71 : We want to know when assumptions are valid. HA(aq) H+from HA A-
Init HAINIT 10-7 0
Change -x +x +x
Equil HAINIT-x 10-7 +x x %ionized Consider a generic Weak Acid
Slide72 : The issue is small Ka with respect
To the initial concentration!! Mass balance Considering a simple system
Do you need to know it? OK this is not a nice equation Hint: no red box
Slide73 : KA= 10-1 10-2 10-3 10-4 5x10-5 5x10-6 10-7 Error too large Error OK Never make
assumption Safe to make assumption iffy
Slide74 : Small K ~ <10-6 Rule of Thumb Sort of small 10-610-3
Slide75 : K=10-11 10-10 10-9 10-8 10-7 5%error What about the other assumption?
contribution of OH- or H+ – x>>10-7
Slide76 : Rule of thumb Must worry about proton contribution
Slide77 : “A” students work
(without solutions manual)
~ 10 problems/night. Dr. Alanah Fitch
Flanner Hall 402
508-3119
afitch@luc.edu
Office Hours Th&F 2-3:30 pm Module #17B:
Acid Base Ionization
Computations
Slide78 : Examples K Init Conc. x>10-7?
HSO4- 1.2x10-2 0.001 yes
Triethylamine 4x10-4 0.2 yes
HF 7.2x10-4 1.0 yes
Acetic Acid 1.8x10-5 0.8355 yes
Acetate 5.55x10-10 0.1 no
Boric Acid 5.8x10-10 0.75