59-291-S1-L5

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1 Renal Function Glomerular filtration Active tubular secretion Passive tubular reabsorption Excretion 59-291 Section 1, Lecture 5 Drug Excretion -most drugs are excreted in urine either as unchanged or drug metabolites

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2 Glomerular Filtration- 1 st step in renal drug excretion Drug enters renal tubule as a dissolved solute Drug filtration rate = Free drug Plasma conc. X Glomerular filtration rate (GFR) For Penicilin G- 40% unbound in plasma; pKa= 2.8; Plasma conc.= 3 m g/mL; Free drug conc.= ? Drug excretion rate- 1200 m g/min Glomerular filtration rate- 100 mL/min Excreted drug = (Filtered+ secreted) - reabsobed

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3 Drug filtration rate = Plasma conc.(free drug) X GFR = 1.2 m g/mL x 100mL/min = 120 units? Active Tubular Secretion -some drugs especially weak acids and bases undergo active tubular secretion by transport systems located in the proximal tubular cells Not affected by plasma protein binding as free drug is transported bound drug dissociates to replace free drug that has been transported.

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4 What is the Drug Secretion rate for Penicilin? Drug Excretion rate = Drug Secretion Rate + Drug filtration rate Drug Secretion Rate = Drug Excretion rate – Drug filtration rate For PenicilinG Drug Secretion Rate = 1200 m g/min – 120 m g/min = 1080 m g/min -Most of drug secreted

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5 Passive Reabsorption -most substances are reabsorbed across renal tubular cells if unionized and lipid soluble Can manipulate urine pH to ensure drugs are not reabsorbed in overdose situations 5.8 = 5.8 + log A-/HA= 1= 1:1 Rate of reabsorbtion = 1.2 m g/mL x 1/2 = 0.6  g/mL increase urine pH to 7.0 7.0 = 5.8 + log A-/HA= 1.2 = 15.8:1= 1.2 m g/mL x 1/16.8 = 0.071 g /mL Renal Clearance= excretion rate/plasma drug concentration (units: L/h) For penicilin: 1200 ug/min/ 3ug/mL= 400 mL/minx60 min/h=24000mL/h= 24000mL/hX 1L/1000mL= 24L/h

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6 Other routes of excretion: Biliary excretion- drugs with mwts >300 excreted in to bile Enterohepatic cycling- Sweat, Saliva-

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7 Pharmacokinetic Calculations Rate of elimination First order Rate =v= [Drug] Plasma k Where k is the elimination rate constant Rate= change in plasma conc /unit time= D [Drug]/min First- Order Kinetics Drug elimination= [drug] Plasma x drug clearance The elimination rate declines as the [drug] Plasma declines Half-life and clearance remain constant if hepatic and renal function do not change

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8 Half-Life (t ½) of a 1 st order reaction -time it takes for the plasma concentration to decrease by ½ t ½ = 0.693/k e 0.693 is the natural log (ln) of 2 Factors that affect t ½ drugs clearance rate volume of distribution affects of disease or age on the above

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9 t ½ is calculated from this experiment k e is the elimination rate constant t ½ = 0.693/k e  k e = 0.693/ t ½ Cl = clearance = V d x k e sub for k e Cl = V d x 0.693/ t ½

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10 Zero-Order Kinetics -rate of elimination is constant t ½  to [drug] plasma Cl  1/ [drug] plasma Zero-Order elimination occurs in overdose situations the various processes by which drugs get eliminated are saturated Zero order- independent of the concentration of drug in the plasma

Practice Questions: 

11 Practice Questions Is a drug with pKa= 3.6 reabsorbed in renal tubules with a pH= 5.6? Why? This drug is a weak acid and is ionized at pH= 5.6. Since the ionized form of drug is not lipid soluble, therefore, is not reabsorbed A patient is overdosed with salicylic acid, which is a weak acid. How do you treat this patient in order to remove the drug faster from his blood. Alkalinizing the urine. Increasing the drug excretion Counteracting the metabolic acidosis