Pythagoras theorem

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www.iPracticeMath.com provides best Math practice through Math practice questions on every Math topic. This presentation shows Pythagoras theorem by how to find Hypotenuse a right angled triangle.

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www.iPracticeMath.com A complete Math Practice platform For k-12 grades. Suggest ways that parents can help their child learn, such as give them practice Math for 30 minutes a day.

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www.iPracticeMath.com Theorem of Pythagoras Pythagoras theorem. Pythagoras theorem was first enunciated by the mathematician Pythagoras . This important theorem about right angled triangles.

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In the figure alongside m E = 90° ∴ Δ DEF is a right angled triangle. The side DF opposite E is its hypotenuse . www.iPracticeMath.com Theorem of Pythagoras D E F (Hypotenuse) 2 = (side one) 2 + (side two) 2

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Seg DE and EF are the sides making the right angle or the sides containing the right angle . www.iPracticeMath.com Theorem of Pythagoras D E F (Hypotenuse) 2 = (side one) 2 + (side two) 2

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Look at the figure alongside. Seg PR is the hypotenuse. www.iPracticeMath.com Theorem of Pythagoras P Q R 2.1 2.8 (Hypotenuse) 2 = (side one) 2 + (side two) 2

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(side PR) 2 = (side PQ) 2 + (side QR) 2 . Seg PR is the hypotenuse. www.iPracticeMath.com Theorem of Pythagoras P Q R 2.1 2.8 (Hypotenuse) 2 = (side one) 2 + (side two) 2

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(side PR) 2 = (side PQ) 2 + (side QR) 2 = (2.1) 2 + (2.8) 2 = 4.41 + 7.84 = 12.25 www.iPracticeMath.com Theorem of Pythagoras P Q R 2.1 2.8 (Hypotenuse) 2 = (side one) 2 + (side two) 2

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(side PR) 2 = 12.25 =1225/100 Side PR = 1225/100 = 3.5 cm www.iPracticeMath.com Theorem of Pythagoras P Q R 2.1 2.8 (Hypotenuse) 2 = (side one) 2 + (side two) 2

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