logging in or signing up chapter4 Desiderio Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINTLite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 375 Category: Entertainment License: All Rights Reserved Like it (0) Dislike it (0) Added: January 16, 2008 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide1: CHEMISTRY 161 Chapter 4 The MoleSlide2: Macroscopic versus Microscopic Worlds 2 H2 + O2 2 H2O 1 liter water contains about 3.3 X 1025 moleculesSlide3: CHEMICAL MASS SCALE standard / calibration atomic mass unit (amu, u) one atom of carbon-12 12 u (exactly) we have to correlate u with kg Slide4: H2O O: 15.999 u H: 1.008 u H: 1.008 u H2O: 18.015 u PSE formula mass: weight of one moleculeSlide5: CaO O: 15.999 u Ca: 40.08 u CaO: 56.08 u formula mass: weight of one molecule correlation between u and kg Slide6: MOLESlide7: one mole of a compound contains the same number of molecules/atoms as the number of atoms in exactly 12 g of 12C Avogadro’s number Na 6.023 x 1023Slide8: 1 mole of H2O 6.023 x 1023 1 mole of 12C 6.023 x 1023 6.023 x 1023 1 mole of NaCl 1 mole of Na 6.023 x 1023 Avogadro’s number links micro and macroscopic world molecules molecules atoms atomsSlide9: 1 mole of H2O 6.023 x 1023 molecules 1 molecule of H2O – 2 H atoms and 1 O atom 1 mole of H2O – 2 mole H atoms and 1 mole O atoms 6.023 x 1023 molecules of H2O 6.023 x 1023 atoms of O 2 x 6.023 x 1023 atoms of HSlide10: H2O O: 15.999 u H: 1.008 u H: 1.008 u H2O: 18.015 u 1 mole of H2O – 18.015 g 15.999 g/mol 1.008 g/mol 1.008 g/mol Na Na NaSlide11: CaO O: 15.999 u Ca: 40.08 u CaO: 56.08 u 1 mole of CaO – 56.08 g Slide12: 1 mole of H2O – 18.015 g 6.023 x 1023 molecules of H2O – 18.015 g one molecule of H2O – 2.99 x 10-23 g molecular weight of one mole of H2O 18.015 g mol-1 Slide13: 2 H2 + O2 2 H2O 2 molecules 1 molecule 2 molecules 2 moles 1 mole 2 moles 4.03176g 31.9988g 36.03g STOICHIOMETRY x g y g 70.0gSlide14: 2 H2 + O2 2 H2O 2 molecules 1 molecule 2 molecules 2 moles 1 mole 2 moles 4.03176g 31.9988g 36.03g STOICHIOMETRY x g y g 70.0gSlide15: Example I: How many grams of iron are in a 15.0 g sample of iron(III) oxide? 1. molecular formula 3. weight of one mole Fe2O3 2. weight of one molecule Fe2O3 159.7 u 159.7 g 4. 1 molecule Fe2O3 contains 2 atoms of Fe 5. 1 mole Fe2O3 contains 2 moles of Fe 159.7 g 111.69 g 15.0 g x g x = 10.5 gSlide16: Example II: How many grams of oxygen are in a 10.0 g sample of nickel (II) nitrate? 1. molecular formula 3. weight of one mole Ni(NO3)2 2. weight of one molecule 4. 1 molecule Ni(NO3)2 contains 6 atoms of O 5. 1 mole Ni(NO3)2 contains 6 moles of O x = 5.25 gSlide17: Example III: How many atoms are in 10 kg of sodium? 1 mole sodium = 22.98977 g 6.023 x 1023 atoms = 22.98977 g x atoms = 10,000 g x = 2.6 x 1026 atomsSlide18: Example IV How heavy are 1 million gold atoms? 1 mole gold = 196.96654 g 6.023 x 1023 atoms = 196.96654 g 1,000,000 atoms = x g x = 3.2 x 10-16 g = 0.32 fgSlide19: Mass Percentage Composition P4O10 = X 100 % = X 100 %Slide20: Example V A sample was analyzed and contains 0.1417 g of nitrogen and 0.4045 g of oxygen. Calculate the percentage composition. 1. mass of whole sample 2. percentages of elements = X 100 %Slide21: EMPIRICAL FORMULA H2O H2O2 MOLECULAR FORMULA HO H2O H2O P4O10 P2O5 P2*2O2*5Slide22: Example A sample contains 0.522 g of nitrogen and 1.490 g of oxygen. Calculate its empirical formula. N2O5Slide23: COMBUSTION CxHy CO2 H2OSlide24: COMBUSTION C3H8 CO2 + H2O 0.013068 g + O2 How many grams of oxygen are consumed? balance equation convert to molesSlide25: The combustion of a 5.217 g sample of a compound of C, H, and O gave 7.406 g CO2 and 4.512 g of H2O. Calculate the empirical formula of the compound. How many grams of Al2O3 are produced when 41.5 g Al react? 2Al(s) + Fe2O3(s) Al2O3(s) + 2 Fe(s) Slide26: LIMITING REACTANT C2H4 + H2O C2H5OHSlide27: excess reactant limiting reactantSlide28: How many grams of NO can form when 30.0 g NH3 and 40.0 g O2 react according to 4 NH3 + 5 O2 4 NO + 6 H2O 2 C2H2 + 5 O2 4 CO2 + 2 H2OSlide29: THE YIELD 2 C2H2 + 5 O2 4 CO2 + 2 H2O theoretical yield of CO2: 10 g actual yield of CO2: 8 g = X 100 % You do not have the permission to view this presentation. In order to view it, please contact the author of the presentation.
chapter4 Desiderio Download Post to : URL : Related Presentations : Share Add to Flag Embed Email Send to Blogs and Networks Add to Channel Uploaded from authorPOINTLite Insert YouTube videos in PowerPont slides with aS Desktop Copy embed code: (To copy code, click on the text box) Embed: URL: Thumbnail: WordPress Embed Customize Embed The presentation is successfully added In Your Favorites. Views: 375 Category: Entertainment License: All Rights Reserved Like it (0) Dislike it (0) Added: January 16, 2008 This Presentation is Public Favorites: 0 Presentation Description No description available. Comments Posting comment... Premium member Presentation Transcript Slide1: CHEMISTRY 161 Chapter 4 The MoleSlide2: Macroscopic versus Microscopic Worlds 2 H2 + O2 2 H2O 1 liter water contains about 3.3 X 1025 moleculesSlide3: CHEMICAL MASS SCALE standard / calibration atomic mass unit (amu, u) one atom of carbon-12 12 u (exactly) we have to correlate u with kg Slide4: H2O O: 15.999 u H: 1.008 u H: 1.008 u H2O: 18.015 u PSE formula mass: weight of one moleculeSlide5: CaO O: 15.999 u Ca: 40.08 u CaO: 56.08 u formula mass: weight of one molecule correlation between u and kg Slide6: MOLESlide7: one mole of a compound contains the same number of molecules/atoms as the number of atoms in exactly 12 g of 12C Avogadro’s number Na 6.023 x 1023Slide8: 1 mole of H2O 6.023 x 1023 1 mole of 12C 6.023 x 1023 6.023 x 1023 1 mole of NaCl 1 mole of Na 6.023 x 1023 Avogadro’s number links micro and macroscopic world molecules molecules atoms atomsSlide9: 1 mole of H2O 6.023 x 1023 molecules 1 molecule of H2O – 2 H atoms and 1 O atom 1 mole of H2O – 2 mole H atoms and 1 mole O atoms 6.023 x 1023 molecules of H2O 6.023 x 1023 atoms of O 2 x 6.023 x 1023 atoms of HSlide10: H2O O: 15.999 u H: 1.008 u H: 1.008 u H2O: 18.015 u 1 mole of H2O – 18.015 g 15.999 g/mol 1.008 g/mol 1.008 g/mol Na Na NaSlide11: CaO O: 15.999 u Ca: 40.08 u CaO: 56.08 u 1 mole of CaO – 56.08 g Slide12: 1 mole of H2O – 18.015 g 6.023 x 1023 molecules of H2O – 18.015 g one molecule of H2O – 2.99 x 10-23 g molecular weight of one mole of H2O 18.015 g mol-1 Slide13: 2 H2 + O2 2 H2O 2 molecules 1 molecule 2 molecules 2 moles 1 mole 2 moles 4.03176g 31.9988g 36.03g STOICHIOMETRY x g y g 70.0gSlide14: 2 H2 + O2 2 H2O 2 molecules 1 molecule 2 molecules 2 moles 1 mole 2 moles 4.03176g 31.9988g 36.03g STOICHIOMETRY x g y g 70.0gSlide15: Example I: How many grams of iron are in a 15.0 g sample of iron(III) oxide? 1. molecular formula 3. weight of one mole Fe2O3 2. weight of one molecule Fe2O3 159.7 u 159.7 g 4. 1 molecule Fe2O3 contains 2 atoms of Fe 5. 1 mole Fe2O3 contains 2 moles of Fe 159.7 g 111.69 g 15.0 g x g x = 10.5 gSlide16: Example II: How many grams of oxygen are in a 10.0 g sample of nickel (II) nitrate? 1. molecular formula 3. weight of one mole Ni(NO3)2 2. weight of one molecule 4. 1 molecule Ni(NO3)2 contains 6 atoms of O 5. 1 mole Ni(NO3)2 contains 6 moles of O x = 5.25 gSlide17: Example III: How many atoms are in 10 kg of sodium? 1 mole sodium = 22.98977 g 6.023 x 1023 atoms = 22.98977 g x atoms = 10,000 g x = 2.6 x 1026 atomsSlide18: Example IV How heavy are 1 million gold atoms? 1 mole gold = 196.96654 g 6.023 x 1023 atoms = 196.96654 g 1,000,000 atoms = x g x = 3.2 x 10-16 g = 0.32 fgSlide19: Mass Percentage Composition P4O10 = X 100 % = X 100 %Slide20: Example V A sample was analyzed and contains 0.1417 g of nitrogen and 0.4045 g of oxygen. Calculate the percentage composition. 1. mass of whole sample 2. percentages of elements = X 100 %Slide21: EMPIRICAL FORMULA H2O H2O2 MOLECULAR FORMULA HO H2O H2O P4O10 P2O5 P2*2O2*5Slide22: Example A sample contains 0.522 g of nitrogen and 1.490 g of oxygen. Calculate its empirical formula. N2O5Slide23: COMBUSTION CxHy CO2 H2OSlide24: COMBUSTION C3H8 CO2 + H2O 0.013068 g + O2 How many grams of oxygen are consumed? balance equation convert to molesSlide25: The combustion of a 5.217 g sample of a compound of C, H, and O gave 7.406 g CO2 and 4.512 g of H2O. Calculate the empirical formula of the compound. How many grams of Al2O3 are produced when 41.5 g Al react? 2Al(s) + Fe2O3(s) Al2O3(s) + 2 Fe(s) Slide26: LIMITING REACTANT C2H4 + H2O C2H5OHSlide27: excess reactant limiting reactantSlide28: How many grams of NO can form when 30.0 g NH3 and 40.0 g O2 react according to 4 NH3 + 5 O2 4 NO + 6 H2O 2 C2H2 + 5 O2 4 CO2 + 2 H2OSlide29: THE YIELD 2 C2H2 + 5 O2 4 CO2 + 2 H2O theoretical yield of CO2: 10 g actual yield of CO2: 8 g = X 100 %